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使用 NodeJS 和 websockets，我正在尝试实现一个在线游戏服务器，对于一个乘数游戏，我让人们四处走动，能够看到彼此，但是当服务器产生新的敌人时，我希望能够广播向所有连接的客户端发送消息。

但是没有客户端首先向服务器发送消息。

例如 - 游戏产生一个敌人，向所有客户端发送信息。

到目前为止我的代码：

/**************************************************
** NODE.JS REQUIREMENTS
**************************************************/

var util = require("util"),                 
// Utility resources (logging, object inspection, etc)

    io = require("socket.io"),              
// Socket.IO

    Player = require("./Player").Player,    // Player class
    Zombie = require("./Zombie").Zombie;

// Socket controller

var socket, 

// Array of connected players   

    players,

    zombies;

var level = 1,
    score = 0,
    levelling = false;



function init() {
    // Create an empty array to store players

    players = [];

    zombies = [];

    // Set up Socket.IO to listen on port 8000

    socket = io.listen(8000);

    // Configure Socket.IO

    socket.configure(function() {
        // Only use WebSockets

        socket.set("transports", ["websocket"]);


        // Restrict log output

        socket.set("log level", 2);
    });

    // Start listening for events

    setEventHandlers();
};

blah blah blah -- tl;dr -- 游戏循环：

function mainLoop(){

//Main loop for the server. Called 60 times a second. May be modified for game  
     speed.
//setTimeout(mainLoop, 1000/5000);

this.broadcast.emit("update"); 

    //THIS broadcast.emit line is where the error is being thrown. I need to know how   
    to broadcast here without the client initializing first.
};

我尝试了一些东西，socket.broadcast.emit("update");，但没有成功。

我曾尝试遍历当前已知的用户并使用“this.emit”，但我总是得到“无法调用未定义的方法发射”，太烦人了。

但是当我让客户端首先发送消息时，例如，当客户端移动时，它会向服务器发送一些信息，服务器会做出以下反应：

 function onSocketConnection(client) {
        util.log("New player has connected: " + client.id);

        // Listen for client disconnected

        client.on("disconnect", onClientDisconnect);

        // Listen for new player message

        client.on("new player", onNewPlayer);

        // Listen for move player message

        client.on("move player", onMovePlayer);

        //listen for deaths

        client.on("death", onPlayerDeath);

        //listen for not moved message, to stop sprite animation

        client.on("not moved", notMoved);
    };

    // Player has moved

    function onMovePlayer(data) {
        // Find player in array

        var movePlayer = playerById(this.id);

        // Player not found

        if (!movePlayer) {
            util.log("Player not found: "+this.id + " when asking if moved");
            return;
        };

        // Update player position
        movePlayer.setX(data.x);
        movePlayer.setY(data.y);
        movePlayer.setDir(data.dir);

        // Broadcast updated position to connected socket clients

        this.broadcast.emit("move player", {id: movePlayer.id, x:
            movePlayer.getX(), y:movePlayer.getY(), dir: movePlayer.getDir()});
    };

然后“this.broadcast.emit”没有问题。不抛出错误。

4

1 回答 1

2

好的，我解决了这个烦恼。我将在同一条船上为其他任何人发布答案。我不得不删除该socket变量，并将io require调用更改io = require("socket.io")为：

io = require("socket.io").listen(8000)

有了这个，我需要更改依赖于变量的所有相应变量socket，例如：

从

socket.sockets.on("connection", onSocketConnection);

到

io.sockets.on("connection", onSocketConnection);

然后广播就可以了，例如：io.sockets.emit("updates")

于 2013-03-19T10:50:57.517 回答