4

我正在使用django-tastypie编写 API 。我有两个自定义权限问题，希望django-guardian可以解决。

我有两个用户组临床医生和患者。临床医生应该能够访问仅属于他们的患者的对象，而患者应该只能访问他们自己创建的对象。

我的代码如下：

class UserResource(ModelResource):
    class Meta:
        queryset = User.objects.all()
        resource_name = 'auth/user'
        excludes = ['email', 'password', 'is_superuser']


class BlogPostResource(ModelResource):
    author = fields.ToOneField(UserResource, 'author', full=True)

    class Meta:
        queryset = BlogPost.objects.all()
        resource_name = 'posts'
        allowed_methods = ["get", "post"]
        # Add it here.
        authentication = BasicAuthentication()
        authorization = DjangoAuthorization()
        filtering = {
            'author': ALL_WITH_RELATIONS,
        }

我如何使用权限来限制对此的访问BlogPostResource？

4

2 回答 2

4

您可以使用自定义授权类来实现这一点，例如：

class CustomAuthorization(Authorization):
    def apply_limits(self, request, object_list):     
        ...
        clin_group = Group.objects.get(name='YOUR GROUP')
        if request and hasattr(request, 'user'):
            if clin_group in request.user.groups.all(): 
                 object_list = object_list.filter(user__in=request.user.patients.all()) # or however you stop clinician>patient relation
            else:
                 object_list = object_list.filter(user=request.user)
        return object_list
于 2013-03-18T13:13:44.000 回答
3

我的最终解决方案基于@JamesO的答案。他的答案的问题是它是在 重写课程之前为旧版本的 django-tastypie 编写的。这是我的代码以供将来参考：Authorization

from tastypie.authorization import Authorization
from django.contrib.auth.models import Group
from extendedusers.models import ExtendedUser


class CustomAuthorization(Authorization):
    def read_list(self, object_list, bundle):
        clinician_group = Group.objects.get(name='clinician')
        if bundle.request and hasattr(bundle.request, 'user'):
            if clinician_group in bundle.request.user.groups.all():
                patients = ExtendedUser.objects.filter(clinician_id=bundle.request.user.id)
                object_list = object_list.filter(author__id__in=patients)
            else:
                object_list = object_list.filter(author=bundle.request.user)
            return object_list
        else:
            return object_list.none()
于 2013-03-18T16:27:48.577 回答