1

因此,在我的第五行代码中[if(length == 2 || 1)],我的 or 语句中出现了一个错误,即 Operator || 对于参数类型 boolean、int 未定义。关于我的语法有什么问题以及如何修复它的任何想法?谢谢!

//Write a program that translates a letter grade into a number grade. Letter grades are
//A B C D F, possibly followed by + or -. Their numeric values are 4, 3, 2, 1, and 0.
//There is no F+ or F-. A + increases the numeric value by 0.3, a - decreases it by     0.3.
//However, an A+ has the value 4.0. All other inputs have value –1.
//Enter a letter grade:

//使用带有方法getNumericGrade的类Grade。

public class Grade {
private double grade = 0.0;
public double getNumericGrade(String letterGrade){
    int length = letterGrade.length();
    if(length == 2 || 1){
        char startChar = letterGrade.charAt(0);
        char endChar = letterGrade.charAt(1);
        switch(startChar){
        case 'A':
            this.grade = 4.0;
            break;
        case 'B':
            this.grade = 3.0;
            break;
        case 'C':
            this.grade = 2.0;
            break;
        case 'D':
            this.grade = 1.0;
            break;
        case 'F':
            this.grade = 0.0;
            break;
        default:
            this.grade = -1;
        }
    if(length == 2){
        switch(endChar){
        case '-':
            this.grade = this.grade - .3;
            break;
        case '+':
            if(startChar != 'A'){
            this.grade = this.grade + .3;
            }
            break;
        default:
            this.grade = -1;
        }
    }
    if(startChar == 'F' && length != 1){
        this.grade = -1;
    }
    }else{
        this.grade = -1;
    }
    return this.grade;
}

}

4

3 回答 3

3

这意味着该||运算符不接受布尔值和 int,您必须给它两个布尔表达式。

if(length == 2 || length ==  1)
于 2013-03-18T00:55:54.580 回答
1

你想说 if(length == 1 || length == 2)。你现在正在做的是说 if(length == 2 OR 1)。前者涉及两个可以评估真假的逻辑语句,后者一方面涉及一个逻辑语句,另一方面涉及一个整数。

计算机不会将 length == 2 OR 1 解释为“如果长度为 1 或 2,则返回 true”,而是“(如果长度等于 2,则返回 true)或(整数 1)”。

于 2013-03-18T01:00:25.863 回答
0

您可以执行以下操作:

if (Arrays.asList(1,2,3).contains(l.lenghth))
   // code
于 2013-03-18T05:30:21.793 回答