更新：不幸的是，我无法完成这项任务，虽然截止日期已经过去，但我觉得我在这方面投入了太多时间，只是把它搁置一边，我知道我已经接近解决方案了。这是我过去几天生成的代码
/*
"[5*sin(3*t+0.523),4*cos(2*t)]"
*/
import java.util.*; //
import javax.swing.*; //
import javax.swing.JFrame; // lets me create the window
import java.awt.Graphics; // for drawing
import java.awt.Point; // allows the use of points
import java.awt.Graphics2D; // for drawing
import javax.swing.JComponent; // for drawing
import javax.swing.JPanel; // for drawing
import java.lang.Math; // for trig
import java.util.Iterator;
import java.util.LinkedList;
import java.util.Queue;
public class Graph
{
//-------------------Queue---String----------------------------------------------------------------//
public static double[] queue_str(String str, double[] results)
{
Queue<Character> token = new LinkedList<Character>();
Queue<Double> numbers = new LinkedList<Double>();
double[] t_vals = new double [5];
int t_vals_len = t_vals.length;
int numbers_sz = 0;
int token_sz = 0;
t_vals[0] = 7.0;
t_vals[1] = 2.0;
t_vals[2] = 3.0;
t_vals[3] = 4.0;
t_vals[4] = 3.0;
char temp_token;
char temp_char;
double p1_num = 0, temp_num = 0, p2_num = 0;
if(results.length == 0){}
for(int i = 0; i < str.length(); i++)
{
if(str.charAt(i) == '*' && str.charAt(i) != 't' || str.charAt(i) == '+'&& str.charAt(i) != 't' || str.charAt(i) == '-' && str.charAt(i) != 't' || str.charAt(i) == '/' && str.charAt(i) != 't')
{
temp_token = str.charAt(i);
token.add(temp_token);
token_sz ++;
String[] parts = str.split("\\" + String.valueOf(temp_token));
String str1 = parts[0];
String str2 = parts[1];
if(str1.matches("-?\\d+(\\.\\d+)?"))
{
p1_num = Double.parseDouble(str1);
numbers.add(p1_num);
numbers_sz ++;
}
if(str2.matches("-?\\d+(\\.\\d+)?"))
{
p2_num = Double.parseDouble(str2);
numbers.add(p2_num);
numbers_sz ++;
}
}
else if(str.charAt(i) == 't')
{
temp_token = str.charAt(i);
String [] t_char = str.split(String.valueOf(temp_token));
for(int k = 0; k < t_vals_len; k++)
{
temp_num = t_vals[k];
numbers.add(temp_num);
numbers_sz ++;
}
}
}
double[] dbl_numbs = new double [numbers_sz];
while(numbers.peek()!=null)
{
for (int iter = 0; iter < numbers_sz; iter++)
{
dbl_numbs [iter] = numbers.poll();
}
}
while(token.peek()!=null)
{
temp_token = token.peek();
token.poll();
if(temp_token== '+')
{
eval_inner_add(dbl_numbs, numbers_sz);
results = eval_inner_add(dbl_numbs,numbers_sz);
}
else if(temp_token == '-')
{
eval_inner_add(dbl_numbs, numbers_sz);
}
else if(temp_token == '*')
{
results = eval_inner_multi(dbl_numbs, numbers_sz);
}
else if(temp_token == '/')
{
eval_inner_div(dbl_numbs, numbers_sz);
}
}
return t_vals;
}
//-----------------Removing---Brackets-------------------------------------------------------------//
public static String [] remove_brackets(String remove_brack)
{
String [] substring = remove_brack.split ("[\\[,\\]]");
String rest_of_str = substring [1];
String rest_of_str_2 = substring [2];
return new String [] {rest_of_str,rest_of_str_2};
}
//-----------------Removing---Parenthesis-------------------------------------------------------------//
public static String [] remove_paren(String remove_paren)
{
String [] substring = remove_paren.split ("[\\(,\\)]");
String rest_of_str = substring [0];
String rest_of_str_2 = substring [1];
return new String [] {rest_of_str,rest_of_str_2};
}
//---------------Retrieving--Far-Left--Number----------------------------------------------------//
public static double get_first_exp (String get_left_exp)
{
double eval_num = 0;
if(get_left_exp.matches("[-]"))
{
String [] check_neg = get_left_exp.split("[\\-]");
String neg_num = check_neg[0];
eval_num = Double.parseDouble(neg_num);
eval_num = eval_num * (-1.0);
return eval_num;
}
else
{
String [] parts = get_left_exp.split("[\\/,\\*,\\+]");
String sub_str_1 = parts [0];
eval_num = Double.parseDouble(sub_str_1);
return eval_num;
}
}
//-------------Evaluating--equations--containing--sine----------------------------------------//
public static double eval_sin (String sin_eq)
{
double number = 0;
String [] split = remove_paren(sin_eq);
String inner_exp = split[1];
double [] nothing = new double [0];
number = get_first_exp (sin_eq);
queue_str(inner_exp, nothing);
return number;
}
//-------------Evaluating--equations--containing--cosine----------------------------------------//
public static double eval_cos (String cos_eq)
{
double number = 0;
double [] nothing = new double [0];
String [] split = remove_paren(cos_eq);
String inner_exp = split[1];
number = get_first_exp (cos_eq);
queue_str(inner_exp, nothing);
return number;
}
//---------------Evalutating--points-------------------------------------------------------------//
public static double[] eval_inner_multi (double [] numbers, int numbers_sz)
{
String nothing = "";
double[] results = new double [numbers_sz];
double first_num = numbers[0];
System.out.println(first_num);
for(int i = 1; i < numbers_sz-1; i++)
{
results[i] = first_num * numbers[i];
System.out.println(results[i]);
}
queue_str(nothing,results);
return results;
}
public static double[] eval_inner_add (double [] numbers, int numbers_sz)
{
String nothing = "";
double[] results = new double [numbers_sz];
double first_num = numbers[0];
for(int i = 1; i < numbers_sz-1; i++)
{
results[i] = first_num + numbers[i];
System.out.println(results[i]);
}
queue_str(nothing,results);
return results;
}
public static double[] eval_inner_sub(double [] numbers, int numbers_sz)
{
double[] t_vals = new double [5];
return t_vals;
}
public static double[] eval_inner_div(double [] numbers,int numbers_sz)
{
double[] t_vals = new double [5];
return t_vals;
}
//------------------------------Main------------------------------------------------------------------------//
public static void main(String[] args)
{
String left_exp = "";
String right_exp = "";
double left_sin_num , right_sin_num, left_cos_num, right_cos_num = 0;
for(String s: args) // taking in user input for command line
{
String [] new_str = remove_brackets(s);
left_exp = new_str[0];
right_exp = new_str[1];
}
if(left_exp.contains("sin")) // add SINE, SIN, COSINE, COS
{
left_sin_num = eval_sin(left_exp);
}
else if (right_exp.contains("sin"))
{
right_sin_num = eval_sin(right_exp);
}
if (right_exp.contains("cos"))
{
right_cos_num = eval_cos(right_exp);
}
else if (left_exp.contains("cos"))
{
left_cos_num = eval_cos(left_exp);
}
}
}
这项任务的目的是创建一个程序来评估参数方程并连接坐标以绘制图形。我遇到的问题是，当我在 queue_str() 函数中发送我的双精度数组以进行评估时，我有两个操作的实例存在于我们面前。我无法正确地将内容发送回 queue_str() 以由第二个操作数评估例如考虑到我的顶级评论中的示例函数我能够发送 3*t 其中 t_vals 是要乘以三个的测试用例. 在这种情况下，我必须将数组的大小设为 -1，因为我必须考虑数组中的第一个和最后一个元素。这就是我卡住的地方我怎样才能正确评估这个表达式？我会很感激任何帮助，我为这一段道歉，我只知道我很接近让它工作。