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我有一个 xml 字符串代码。这个字符串可以是格式正确的，也可以不是格式正确的，我应该返回一个格式正确的 xml 字符串。

我使用了这段代码，它工作得很好：

try {
            final Document document = parseXmlFile(code);
                OutputFormat format = new OutputFormat(document);
            format.setLineWidth(65);
            format.setIndenting(true);
            format.setIndent(2);
            Writer out = new StringWriter();
            XMLSerializer serializer = new XMLSerializer(out, format);
            serializer.serialize(document);
            newcode = out.toString();
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
private Document parseXmlFile(String in) {
    try {
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        InputSource is = new InputSource(new StringReader(in));
        return db.parse(is);
    } catch (ParserConfigurationException e) {
        throw new RuntimeException(e);
    } catch (SAXException e) {
        throw new RuntimeException(e);
    } catch (IOException e) {
        throw new RuntimeException(e);
    }
}

但我发现了一个带有这个声明的 xml 字符串的错误：

<?xml version=

1.0 编码= utf-8 ?>

这是给定的错误：

org.xml.sax.SAXParseException：XML 声明中“版本”后面的值必须是带引号的字符串。

我也试过这段代码，但我得到了同样的错误：

private static String prettyFormat(String input, int indent) {
    try {
        Source xmlInput = new StreamSource(new StringReader(input));
        StringWriter stringWriter = new StringWriter();
        StreamResult xmlOutput = new StreamResult(stringWriter);
        TransformerFactory transformerFactory = TransformerFactory.newInstance();
        transformerFactory.setAttribute("indent-number", indent);
        Transformer transformer = transformerFactory.newTransformer(); 
        transformer.setOutputProperty(OutputKeys.INDENT, "yes");
        transformer.transform(xmlInput, xmlOutput);
        return xmlOutput.getWriter().toString();
    } catch (Exception e) {
        throw new RuntimeException(e); // simple exception handling, please review it
    }
}

你有什么想法我可以解决它吗？可能不删除原始声明。

谢谢！！

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0 回答 0