sql - 按多列分组，在第一个按列分组时求和

Question

我正在编写一个分组两列的查询。这意味着，它将把 Col1 和 Col2 放在同一个组中。

如何根据 Group Col1 对记录进行 SUM？

到目前为止我有这个：http ://sqlfiddle.com/#!3/eada2/1

谢谢

Answer 1

在我看来，这是一个看起来更简洁的解决方案 - 它不需要连接并使用“分区依据”来计算个人计数：

WITH activityCounts as (
    select
        activityId,
        docuType,
        count(activityId) OVER(PARTITION BY activityId) as activityIdCount,
        count(docuType) OVER(PARTITION BY activityId, docuType) as docuTypeCount,
        SUM(CASE WHEN [sent] != '1-1-1900' THEN 1 END) OVER(PARTITION BY activityId, docuType) AS [Sent],
        SUM(CASE WHEN [approved] != '1-1-1900' THEN 1 END) OVER(PARTITION BY activityId, docuType) AS [Approved]
    from ER
)
SELECT
    activityId,
    docuType,
    docuTypeCount,
    CONVERT(DECIMAL(16,2), (COUNT(docuTypeCount) * 100.00 / activityIdCount)) as [Total DocuType in Activity],
    [Sent],
    [Approved]
FROM activityCounts
GROUP BY
    activityId,
    docuType,
    activityIdCount,
    docuTypeCount,
    [Sent],
    [Approved]

这是sqlfiddle 的链接

Answer 2

我能够解决它如下：

WITH cteActivityIds (activityId, allDocuByActivity)
AS
  (SELECT activityId, COUNT(*) AS allDocuByActivity FROM #ER GROUP BY activityId)
SELECT
      E.activityId AS [Actiivty ID],
      docuType AS [Docu Type],
      COUNT(docuType),
      CONVERT(DECIMAL(16,2), (COUNT(docuType) * 100.00 / t.allDocuByActivity)) [Total     DocuType in Activity],
      SUM(CASE WHEN [sent] != '1-1-1900' THEN 1 END) AS [Sent],
      SUM(CASE WHEN [approved] != '1-1-1900' THEN 1 END) AS [Approved]
FROM
      #ER AS E
INNER JOIN cteActivityIds AS t 
  ON E.activityId = t.activityId
GROUP BY
     E.activityId, docuType, t.allDocuByActivity

谢谢

Answer 3

你只需要放一个聚合函数t.allDocuByActivity

MIN(t.allDocuByActivity) AS [Total DocuType in Activity],

但是，由于您的标签是DocuType. 你不需要DISTINCT吗？