我的脚本正在打开旧版本的应用程序（我编写的）。我搜索了高清，找不到旧应用程序。新版本位于应用程序文件夹中。该脚本位于脚本文件夹中。
我创建了一个新文件夹并将脚本和新应用程序放入其中。运行脚本仍然会打开错误的应用程序。App2 是问题孩子。
错误的路径从何而来？
如何：
将脚本指向正确的应用程序？我不想要脚本中的路径。
找到旧的应用程序并删除它？
property checkInterval : 5 -- Number of seconds between checks. Adjust to requirement.
global App1WasOpen, GUIScriptingWasEnabled, previousText
on run
-- When the script starts up, note if App1 is running and GUI Scripting is enabled.
tell application "App1" to activate
tell application "System Events"
set App1WasOpen to (application process "App1" exists)
set GUIScriptingWasEnabled to (UI elements enabled)
end tell
-- Enable GUI Scripting if nec. and give the 'previousText' variable an initial value.
switchGUIScripting(true)
set previousText to ""
end run
on idle
-- Each time the script's polled by the system, check that App1's open.
tell application "System Events" to set App1IsOpen to (application process "App1" exists)
if (App1gIsOpen) then
set App1WasOpen to true
-- Get the latest value for 'beam'.
tell application "App1"
set hdg to getHeading
set beam to hdg as string
end tell
if ((count beam) < 3) then set beam to text -3 thru -1 of ("000" & beam)
-- If it's changed since the last check, enter it into App2 and keep it for later checks.
if (beam is not previousText) then
--display dialog "Opening App2" buttons {"OK"}
tell application "App2" to launch
--activate application "App2"
tell application "System Events"
set startTime to current date
repeat until exists (text field 1 of window "App2" of application process "App2")
if (current date) - startTime is greater than 5 then
error "Could not find text field 1 of window AppB of application process App2"
exit repeat
end if
delay 0.2
end repeat
tell application process "App2"
try
set value of text field 1 of window "App2" to beam
end try
end tell
end tell
--tell application "App1" to activate
set previousText to beam
end if
-- Request the next 'idle' event in 'checkInterval' seconds' time.
return checkInterval
else if (App1WasOpen) then
-- App1 was open at the last check, but isn't now. Tell this script applet to quit.
quit
-- It'll actually quit on the next idle event, so request a short interval.
return 1
end if
end idle
-- Unless GUI Scripting was already on when the script started to run, turn it on or off as per the parameter.
on switchGUIScripting(onOff) -- 'onOff' is 'true' for on, 'false' for off.
if (not GUIScriptingWasEnabled) then
tell application "System Events"
activate
set UI elements enabled to (onOff)
end tell
end if
end switchGUIScripting
-- When this applet's told to quit, restore the previous GUI Scripting state before it does.
on quit
switchGUIScripting(false)
continue quit
end quit
跟进：我使用 Dock 中应用程序图标上的“在 Finder 中显示”指向我删除的 17 个 Xcode 档案。现在脚本反复出现“发生-10660 类型错误”的消息，并且App2 永远不会打开。
我打开脚本编辑器，将代码复制到一个新的脚本窗口并用不同的名称编译它。仍然没有打开 App2。