1

假设我有两个数组：

var arrOne:Array = ["fish", "cat", "dog", "tree", "frog"];
var arrTwo:Array = ["cat", "cat", "fish", "dog", "fish"];

我需要能够比较它们以确定以下内容：

  • 在同一位置有多少匹配项（在上面的情况下将是 1：arrOne[1] 和 arrTwo[1] 都是 cat）。
  • 有多少匹配项不在同一位置（在上面的这种情况下，有 2 个：猫和鱼）。

这会将用户的输入与随机生成的值数组进行比较；基本上，我希望能够说“你有一个正确的位置在正确的位置，还有两个正确的位置但在错误的位置”。希望这是有道理的。任何帮助，将不胜感激！

4

1 回答 1

0

我只会以常见的方式比较元素。唯一的问题是我们应该如何对待第二种情况的“鱼”。

这是我针对两种情况的解决方案。1 - 如果我们不关心重复的项目，2 - 如果我们关心。

<?xml version="1.0" encoding="utf-8"?>
<s:Application xmlns:fx="http://ns.adobe.com/mxml/2009" 
           xmlns:s="library://ns.adobe.com/flex/spark" 
           xmlns:mx="library://ns.adobe.com/flex/mx" minWidth="955" minHeight="600">
<fx:Script>
    <![CDATA[
        import mx.controls.Alert;
        import mx.events.FlexEvent;

        private var arrOne:Array = ["fish", "cat", "dog", "tree", "frog"];
        private var arrTwo:Array = ["cat", "cat", "fish", "dog", "fish"];

        protected function compare():void
        {
            var rule1:int = 0;
            var rule2:int = 0;

            for (var i: int = 0; i < arrOne.length; i++)
            {
                for (var j: int = 0; j < arrTwo.length; j++)
                {
                    if (arrOne[i] == arrTwo[j])
                    {
                        if (i == j)
                            rule1 ++;
                        else
                            rule2 ++;
                    }
                }
            }

            Alert.show("You got " + rule1.toString() + " correct and in the right spot, and " + rule2.toString() + " correct but in the wrong spot");

        }

        protected function compareWithoutRepeat():void
        {
            var rule1:int = 0;
            var rule2:int = 0;
            var temp:Array = new Array();

            for (var i: int = 0; i < arrOne.length; i++)
            {
                for (var j: int = 0; j < arrTwo.length; j++)
                {
                    if (arrOne[i] == arrTwo[j])
                    {
                        if (i == j)
                            rule1 ++;
                        else
                        {
                            var flag:Boolean = false; //is there the same word in the past?
                            for (var k:int = 0; k < temp.length; k++)
                            {
                                if (temp[k] == arrTwo[j])
                                {
                                    flag = true;
                                    break;
                                }

                            }

                            if (!flag) //the word is new, count it!
                            {
                                rule2 ++;
                                temp.push(arrTwo[j]);
                            }

                        }
                    }
                }
            }

            Alert.show("You got " + rule1.toString() + " correct and in the right spot, and " + rule2.toString() + " correct but in the wrong spot");

        }
    ]]>
</fx:Script>
<s:Button x="10" y="10" width="153" label="Compare" click="compare()"/>
<s:Button x="10" y="39" label="Compare without repeat" click="compareWithoutRepeat()"/>
</s:Application>
于 2013-03-16T09:05:53.113 回答