0

我是使用 Google Maps API 的新手，我正在使用一些不起作用的 Google 文档的示例代码，我想知道是否有人可以帮助我解决为什么它对我不起作用？这是代码本身：<script type="text/javascript" src="https://maps.googleapis.com/maps/api/js?sensor=true" ></script>

    <script>
  var directionDisplay;
  var directionsService = new google.maps.DirectionsService();
  var map;

  function initialize() {
    directionsDisplay = new google.maps.DirectionsRenderer();
    var chicago = new google.maps.LatLng(41.850033, -87.6500523);
    var mapOptions = {
      zoom:7,
      mapTypeId: google.maps.MapTypeId.ROADMAP,
      center: chicago
    }
    map = new google.maps.Map(document.getElementById('map-canvas'), mapOptions);
    directionsDisplay.setMap(map);
  }

  function calcRoute() {
    var start = document.getElementById('start').value;
    var end = document.getElementById('end').value;
    var request = {
        origin:start,
        destination:end,
        travelMode: google.maps.DirectionsTravelMode.DRIVING
    };
    directionsService.route(request, function(response, status) {
      if (status == google.maps.DirectionsStatus.OK) {
        directionsDisplay.setDirections(response);
      }
    });
  }
</script>

这是HTML：

`  <body onload="initialize()">
<div>
<b>Start: </b>
<select id="start" onchange="calcRoute();">
  <option value="chicago, il">Chicago</option>
  <option value="st louis, mo">St Louis</option>
  <option value="joplin, mo">Joplin, MO</option>
  <option value="oklahoma city, ok">Oklahoma City</option>
  <option value="amarillo, tx">Amarillo</option>
  <option value="gallup, nm">Gallup, NM</option>
  <option value="flagstaff, az">Flagstaff, AZ</option>
  <option value="winona, az">Winona</option>
  <option value="kingman, az">Kingman</option>
  <option value="barstow, ca">Barstow</option>
  <option value="san bernardino, ca">San Bernardino</option>
  <option value="los angeles, ca">Los Angeles</option>
</select>
<b>End: </b>
<select id="end" onchange="calcRoute();">
  <option value="chicago, il">Chicago</option>
  <option value="st louis, mo">St Louis</option>
  <option value="joplin, mo">Joplin, MO</option>
  <option value="oklahoma city, ok">Oklahoma City</option>
  <option value="amarillo, tx">Amarillo</option>
  <option value="gallup, nm">Gallup, NM</option>
  <option value="flagstaff, az">Flagstaff, AZ</option>
  <option value="winona, az">Winona</option>
  <option value="kingman, az">Kingman</option>
  <option value="barstow, ca">Barstow</option>
  <option value="san bernardino, ca">San Bernardino</option>
  <option value="los angeles, ca">Los Angeles</option>
</select>
</div>`
4

3 回答 3

1

你有元素来获取start和end值吗？当我从joliet到naperville时，此代码有效：

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?sensor=false"></script>
<style>
#map-canvas {height:500px;width:500px;}
</style>
</head>

<body onload="initialize()">
<div id="map-canvas"></div>
<div>
<b>Start: </b>
<select id="start" onchange="calcRoute();">
  <option value="chicago, il">Chicago</option>
  <option value="st louis, mo">St Louis</option>
  <option value="joplin, mo">Joplin, MO</option>
  <option value="oklahoma city, ok">Oklahoma City</option>
  <option value="amarillo, tx">Amarillo</option>
  <option value="gallup, nm">Gallup, NM</option>
  <option value="flagstaff, az">Flagstaff, AZ</option>
  <option value="winona, az">Winona</option>
  <option value="kingman, az">Kingman</option>
  <option value="barstow, ca">Barstow</option>
  <option value="san bernardino, ca">San Bernardino</option>
  <option value="los angeles, ca">Los Angeles</option>
</select>
<b>End: </b>
<select id="end" onchange="calcRoute();">
  <option value="chicago, il">Chicago</option>
  <option value="st louis, mo">St Louis</option>
  <option value="joplin, mo">Joplin, MO</option>
  <option value="oklahoma city, ok">Oklahoma City</option>
  <option value="amarillo, tx">Amarillo</option>
  <option value="gallup, nm">Gallup, NM</option>
  <option value="flagstaff, az">Flagstaff, AZ</option>
  <option value="winona, az">Winona</option>
  <option value="kingman, az">Kingman</option>
  <option value="barstow, ca">Barstow</option>
  <option value="san bernardino, ca">San Bernardino</option>
  <option value="los angeles, ca">Los Angeles</option>
</select>
</div>`
        <script>
  var directionDisplay;
  var directionsService = new google.maps.DirectionsService();
  var map;

  function initialize() {
    directionsDisplay = new google.maps.DirectionsRenderer();
    var chicago = new google.maps.LatLng(41.850033, -87.6500523);
    var mapOptions = {
      zoom:7,
      mapTypeId: google.maps.MapTypeId.ROADMAP,
      center: chicago
    }
    map = new google.maps.Map(document.getElementById('map-canvas'), mapOptions);
    directionsDisplay.setMap(map);
  }

  function calcRoute() {
    var start = document.getElementById('start').value;
    var end = document.getElementById('end').value;
    var request = {
        origin:start,
        destination:end,
        travelMode: google.maps.DirectionsTravelMode.DRIVING
    };
    directionsService.route(request, function(response, status) {
      if (status == google.maps.DirectionsStatus.OK) {
        directionsDisplay.setDirections(response);
      }
    });
  }
</script>
</body>
</html>
于 2013-03-15T16:32:07.267 回答
1

在结束组合框的 div 之后，似乎也有一个错误的 `。不会造成伤害，但不属于。

于 2013-03-18T14:54:05.753 回答
0

需要调用 initialize() 函数。它可以在这样的<body>标签中：

<body onload="initialize();">
于 2013-03-15T16:27:39.837 回答