下面的代码只是做一个QTimer
with QLCDNumber
。我想在程序启动后 4 秒后显示一个消息对话框。但是,当消息对话框弹出时,时间QLCDNumber
不会改变。即使弹出消息对话框,我应该怎么做才能使该程序保持计时?
import sys
from PyQt4.QtGui import *
from PyQt4.QtCore import *
class MainWindow(QWidget):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.resize(800,600)
self.lcdNumber = QLCDNumber()
self.lcdNumber.setNumDigits(8)
layout = QVBoxLayout(self)
layout.addWidget(self.lcdNumber)
self.currentTime = QTime(0,0,0)
self.lcdNumber.display(self.currentTime.toString('hh:mm:ss'))
self.timer = QTimer(self)
self.timer.timeout.connect(self.updateLcdNumberContent)
self.timer.start(1000)
def updateLcdNumberContent(self):
self.currentTime = self.currentTime.addSecs(1)
self.lcdNumber.display(self.currentTime.toString('hh:mm:ss'))
if self.currentTime == QTime(0,0,4) :
msgBox = QMessageBox()
msgBox.setWindowTitle('iTimer')
msgBox.setIcon (QMessageBox.Information)
msgBox.setText("Time Out !!")
stopButton = msgBox.addButton("Stop", QMessageBox.ActionRole)
ignoreButton = msgBox.addButton(QMessageBox.Ignore)
stopButton.clicked.connect(self.timer.stop)
msgBox.show()
# msgBox.exec_()
if __name__ == '__main__':
app =QApplication(sys.argv)
frame = MainWindow()
frame.show()
sys.exit(app.exec_())