0

Trying to catch a null or 0 input. If a null input is made, the app crashes, if a 0 is input, it passes through the error and returns strange math!

case_cost = (EditText) findViewById(R.id.case_cost);
dilution = (EditText) findViewById(R.id.dilution);
answer =(TextView) findViewById(R.id.answer);
ounces_pc = (TextView) findViewById(R.id.ounces_pc);

Button finishBtn = (Button) findViewById(R.id.button3);
finishBtn.setOnClickListener (new View.OnClickListener() {
    @Override
        public void onClick(View v) {
        // TODO Method 
        if (((Float.valueOf(dilution.getText().toString())) == 0) ||   
                         (dilution.getText().equals(null)))   {

    String errMsg = "Missing Dilution";
        answer.setText(errMsg);

    }   else;

Debug Info:

StringToReal.invalidReal(String, boolean) line: 63  
StringToReal.parseFloat(String) line: 289   
Float.parseFloat(String) line: 300  
Float.valueOf(String) line: 337 
UccActivity$1.onClick(View) line: 47    
Button(View).performClick() line: 4102  
View$PerformClick.run() line: 17063 
Handler.handleCallback(Message) line: 615   
ViewRootImpl$ViewRootHandler(Handler).dispatchMessage(Message) line: 92 
Looper.loop() line: 155 
ActivityThread.main(String[]) line: 5454    
Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not   
available [native method]   
Method.invoke(Object, Object...) line: 511  
ZygoteInit$MethodAndArgsCaller.run() line: 1029 
ZygoteInit.main(String[]) line: 796 
NativeStart.main(String[]) line: not available [native method]  
Thread [<10> Binder_2] (Running)    
Thread [<9> Binder_1] (Running)"
4

2 回答 2

0

您应该在检查值之前检查 Null。否则,当它检查 0 并且值为 Null 时,它将抛出异常。

于 2013-03-15T02:26:33.170 回答
0

这种方法将允许您输入无效的字符串(字母)并且不会崩溃(您将按原样进行)。此外,您的 0 检查不起作用,因为您将 int 与 float 进行比较..您应该使用 0f

String text = dilution.getText().toString();
if (TextUtils.isEmpty(text)) {
  answer.setText("Empty input");
  return;
}

try {
    Float value = Float.valueOf(text);

    if (value == null || value == 0f) {
        answer.setText("Zero");
    }
} catch (NumberFormatException e) {
    answer.setText("Invalid input");
}
于 2013-03-15T03:33:58.527 回答