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有没有办法使用IEnumerable For Each-Loop 来解析 a 中的多个定义SortedDictionary？我想基本上将它用作我猜的简单数据库结构。例如，假设我的字典用于旋转文章，如下所示。对于句子中的每个单词（我的字符串），我会使用同义词（我的定义）创建该字符串的新版本。这甚至是最好的选择吗？这是我到目前为止所拥有的：

string testSentence = "Take it or beat it.";

List<string> allSynonyms = SynonymUtility.AlternativesOf(testSentence).ToList();
variations.AddRange(allSynonyms);


public class SynonymUtility
{
    private static readonly SortedDictionary<char, string> synonymList = new SortedDictionary<char, string>
    {
        {'but', "however"},
        {'take', "abduct, abstract, accroach"},
        {'beat', "hit, lash, punch, shake"},
        {'end', " butt, confine, cusp"};
    }

    public static IEnumerable<string> AlternativesOf(string arg)
    {
        arg = arg.ToLower();
        string[] words = arg.Split(" "));
        //END HERE I AM STUCK...
    }

如您所见，我正在寻找解决方案，但我不知道如何获取每个拆分词并将它们替换为字典中的每个同义词。每次尝试只会替换一个项目......所以最后会有9个句子串的排列。

无论如何，任何帮助将不胜感激。

4

1 回答 1

5

这解决了你的问题：

我已经修改了同义词字典的结构，以便值是列表：

    private static readonly SortedDictionary<string, List<string>> synonymList 
            = new SortedDictionary<string, List<string>>
            {
                {"but", new List<string> { "however" }},
                {"take", new List<string> { "abduct", "abstract", "accroach"}},
                {"beat", new List<string> {"hit", "lash", "punch", "shake"}},
                {"end",  new List<string> {"butt", "confine", "cusp"}}
            };

输出所有替代句子的功能：

    public static IEnumerable<string> AlternativesOf(string arg)
    {
        //First of all, build up a 2d array of all your options
        var words = arg.Split(' ').Select(w=> w.ToLower()).ToList();
        var options = new List<List<string>>();

        foreach (var word in words)
        {
            if (synonymList.ContainsKey(word))
            {
                //Add the original word to the list of synonyms
                options.Add(synonymList[word]
                               .Concat(new List<string> { word }).ToList());
            }
            else
            {
                //Just use the original word only
                options.Add(new List<string> { word });
            }
        }

        //Now return all permutations of the 2d options array
        return AllPermutationsOf("", options, 0);
    }

获取所有排列的函数：

    public static IEnumerable<string> AllPermutationsOf
           (string sentence, List<List<string>> options, int count)
    {
        if (count == options.Count)
        {
            yield return sentence;
        }
        else
        {
            foreach (string option in options[count])
            {
                foreach (var childOption in AllPermutationsOf
                             (sentence + " " + option, options, count + 1))
                {
                    yield return childOption;
                }
            }
        }
    }

示例用法：

 string testSentence = "Take it or beat it.";
 var alternatives = AlternativesOf(testSentence).ToList();

        /*  Output:

            abduct it or hit it.
            abduct it or lash it.
            abduct it or punch it.
            abduct it or shake it.
            abduct it or beat it.
            abstract it or hit it.
            abstract it or lash it.
            abstract it or punch it.
            abstract it or shake it.
            abstract it or beat it.
            accroach it or hit it.
            accroach it or lash it.
            accroach it or punch it.
            accroach it or shake it.
            accroach it or beat it.
            take it or hit it.
            take it or lash it.
            take it or punch it.
            take it or shake it.
            take it or beat it. */
于 2013-03-14T23:34:29.280 回答