php - 如何使用 php 代码显示打印标签

Question

如果 $data_common[$datacntr]['SKU'] = something 我想要一个让打印标签可见的条件

 echo <a href="#" onclick="Popup=window.open(\'printLabel.php?OrderID=' . $orderId . '& Name=' . $Name . '&ShippingAddress=' . $ShippingAddress . '& AddressLine1=' . $AddressLine1 . ' &AddressLine2=' . $AddressLine2 . '&AddressLine3=' . $AddressLine3 . '&City=' . $City . '&County=' . $County . '&District=' . $District . '&StateOrRegion=' . $StateOrRegion . '&PostalCode=' . $PostalCode . '&Phone=' . $Phone . '&platform=' . $platform . '\',\'Popup\',\'toolbar=no,location=no,status=no,menubar=no,scrollbars=yes,resizable=no, width=700,height=600,left=430,top=23\'); return false;"><img src="images/printLabel.png" alt="Print Lable"></a></td>

别的什么都没有

Answer 1

<?php if (isset($data_common[$datacntr]['SKU']) && $data_common[$datacntr]['SKU'] == "something") : ?>
     <?php echo '<a href="#" onclick="Popup=window.open(\'printLabel.php?OrderID=' . $orderId . '& Name=' . $Name . '&ShippingAddress=' . $ShippingAddress . '& AddressLine1=' . $AddressLine1 . ' &AddressLine2=' . $AddressLine2 . '&AddressLine3=' . $AddressLine3 . '&City=' . $City . '&County=' . $County . '&District=' . $District . '&StateOrRegion=' . $StateOrRegion . '&PostalCode=' . $PostalCode . '&Phone=' . $Phone . '&platform=' . $platform . '\',\'Popup\',\'toolbar=no,location=no,status=no,menubar=no,scrollbars=yes,resizable=no, width=700,height=600,left=430,top=23\'); return false;"><img src="images/printLabel.png" alt="Print Lable"></a>' ?>
<?php endif; ?>

if 语句中的第一个条件将检查该$data_common[$datacntr]['SKU']键是否存在。第二个是它是否等于某物（将“某物”更改为您的值）。

希望这可以帮助 ：）

斯托扬

Answer 2

$label= (isset($data_common[$datacntr]['SKU']) && !empty($data_common[$datacntr]['SKU']))?'YOuR LABEL CODE':'';

echo $label;