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我正在尝试编写一个 MySQL 查询,在其中提取卖家的信息和她最受欢迎的产品。这是由页面浏览量最多的产品决定的,即MAX(page_views).

下面的查询只是随机抽取一个产品,而不是页面浏览量最多的产品。

"SELECT 
     seller.id, seller.language, seller.shop_name,seller.story, 
     seller.eng_story, product.id, product.image_thumb, product.title, 
     product.eng_title, product.price, MAX(product.page_views) 
  FROM seller 
     INNER JOIN product ON seller.id=product.seller_id 
  WHERE seller.handpicked='y' AND seller.shop_active='y' 
  GROUP BY seller.id 
  ORDER BY product.page_views
  LIMIT 0,5"

或者更好地说,page_views实际上是正确的数字,但是我如何让其他产品字段(id、图像、标题等)与页面浏览量最多的产品相关。

表数据:

卖方:

id | language | shop_Name | story     | eng_story   | handpicked | active
1  |   1      | mitienda  | hola mundo| Hello world | Y          | Y
2  |   1      | sisenor   | bonita    | beautiful   | N          | Y
3  |   2      | new_world | mi vida   | my life     | Y          | Y

产品:

id | seller_id | image_thumb | title    | eng_title | price | page Views
1  |  1        | /images/..  | sombrero | hat       | $5    | 10
2  |  1        | /images/..  | bufanda  | scarf     | $25   | 30
3  |  2        | /images/..  | arte     | art       | $15   | 15
4  |  3        | /images/..  | joyeria  | jewlery   | $10   | 1
5  |  2        | /images/..  | canasta  | basket    | $21   | 13
6  |  3        | /images/..  | ropa     | clothes   | $13   | 6

预期结果(精简):

seller.id | shop_name | product.id | pageviews | title    | price
  1       |  miteinda |     2      |    30     |  bufanda | $25
  3       |  newworld |     6      |     6     |  ropa    | $13

结果应列出精心挑选的卖家信息以及按浏览量列出的最受欢迎的产品。卖家按浏览量排序,总共限制为 5 个卖家。

4

1 回答 1

19
SELECT  a.ID SellerID,
        a.Shop_Name,
        b.ID ProductID,
        b.pageViews,
        b.title,
        b.Price
FROM    seller a
        INNER JOIN Products b
            ON a.id = b.seller_ID
        INNER JOIN
        (
            SELECT  seller_ID, MAX(pageViews) max_view
            FROM    products
            GROUP   BY seller_ID
        ) c ON  b.seller_ID = c.seller_ID AND
                b.pageViews = c.max_View
WHERE   a.handpicked = 'Y' AND a.active = 'Y'

输出

╔══════════╦═══════════╦═══════════╦═══════════╦═════════╦═══════╗
║ SELLERID ║ SHOP_NAME ║ PRODUCTID ║ PAGEVIEWS ║  TITLE  ║ PRICE ║
╠══════════╬═══════════╬═══════════╬═══════════╬═════════╬═══════╣
║        1 ║ mitienda  ║         2 ║        30 ║ bufanda ║ $25   ║
║        3 ║ new_world ║         6 ║         6 ║ ropa    ║ $13   ║
╚══════════╩═══════════╩═══════════╩═══════════╩═════════╩═══════╝
于 2013-03-14T06:30:41.853 回答