我使用数据库中的 json 数据创建了谷歌饼图。饼图是用图例名称创建的,但我也想显示带有值的图例,即除了饼图之外的带有值的名称。我正在尝试不同的东西,但我完全被这个难住了。
我正在实现的谷歌饼图代码是(片段): -
function drawChart(data)
{
var hi_cnt = data.length;
var gdata = new google.visualization.DataTable();
var total = 0;
gdata.addColumn('string', 'Task');
gdata.addColumn('number', 'Hours Per Day');
gdata.addRows(hi_cnt);
for (var i= 0;i < hi_cnt; i++)
{
gdata.setCell(i, 0, data[i]['name']);
gdata.setCell(i, 1, parseInt(data[i]['count']));
}
var options = {
title: 'Number of Issues By Type',
'width': 750,
'height': 450,
backgroundColor: '#EEE',
legend: {position: 'right'},
areaOpacity: 1.0,
sliceVisibilityThreshold:0,
//vAxis: {format: '# $'},
//hAxis: {title: '????', titleTextStyle: {color: 'blue'}, slantedText: true, viewWindow: {min: 39, max: 52}},
//colors: ['CCFFCC', '66CC66', 'FF9999'],
//animation: {duration: 1000, easing: 'out'}
};
var chart = new google.visualization.PieChart(document.getElementById('outer_tableDiv'));
chart.draw(gdata, options);
}
function getHealthReport()
{
var dataString = {auth_token: sessionStorage.auth_token,};
var mh_url = MH_HOST + '/reports/get_health_issues_report.json';
$.ajax(
{
type: "POST",
url: mh_url,
data: dataString,
dataType: "json",
success: function (data)
{
drawChart(data);
},
error: function (data)
{
alert("fail");
}
});
}
谁能帮帮我吗..