c - 试图编写一个简单的结构基础代码......没有得到？

Question

抱歉，我认为我真的把基于结构的几行代码搞砸了……因为我是新手，最近几天努力理解 C。请检查以下代码并指导我哪里错了……谢谢！

#include <stdio.h>
#include <stdlib.h>
#include <string.h>


struct family{

       char name[20];
       int age;
       char father[20];
       char mother[20];

       };

 //Function to compares two strings and returns 1 or 0  

char siblings(struct family member1, struct family member2)
{
     if(strcmp(member1.mother, member2.mother)==0)
         return 1;
     else
         return 0;
 }

int main()
{

//Following structure variables are decleared

    struct family member1;
    struct family member2;

  //structure variables initilized with a string

    member1.mother = "Rosy";
    member2.mother = "Rosy";

//This function compares two strings and returns 1 or 0

    siblings(member1.mother, member2.mother);

//trying to print resulst with respect to return from function 

     printf("%S\n",siblings(member1.mother, member2.mother)?"yes":"No");


    system("PAUSE");
    return 0;
}

Answer 1

替换以下内容：

1-1：%S应该换成%d

printf("%S\n",siblings(member1.mother, member2.mother)?"yes":"No");

bool1-2：返回或int返回 0 或 1会更好。

char siblings(struct family member1, struct family member2)

2：“暂停”应该是“暂停”

system("PAUSE");

3：strcpy用于以下。

member1.mother = "Rosy";
member2.mother = "Rosy";

Answer 2

代替

member1.mother = "Rosy";
member2.mother = "Rosy";

和

strcpy(member1.mother, "Rosy");
strcpy(member2.mother, "Rosy");

这是因为成员mother不是指针，它是一个数组

编辑

siblings(member1, member2)不应该给兄弟姐妹打电话siblings(member1.mother, member2.mother)