我有带有pyst lib的基本python agi代码:
extensions.conf
[from-internal]
exten => _.,1,answer()
exten => _.,2,AGI(test.py)
我在 /var/lib/asterisk/agi-bin 中有 test.py 作为
#!/usr/bin/python
import sys
import os
from agi import AGI
def test_call(agi = None,text = ""):
agi.say_alpha(text, "#")
agi.hangup()
if __name__ == "__main__":
text = 'abcdefr'
agi = AGI()
test_call(agi,text)
我有一个来自 pyst lib 的文件 agi.py。
当我尝试调用这个 agi 时,我遇到了这个问题
Executing [123@from-internal:1] Answer("SIP/12345-00000016", "") in new stack
[Mar 14 00:01:29] NOTICE[2790]: res_rtp_asterisk.c:2358 ast_rtp_read: Unknown RTP codec 126 received from '169.254.38.82:20338'
-- Executing [123@from-internal:2] AGI("SIP/12345-00000016", "test.py") in new stack
-- Launched AGI Script /var/lib/asterisk/agi-bin/test.py
test.py: Failed to execute '/var/lib/asterisk/agi-bin/test.py': No such file or directory
-- Auto fallthrough, channel 'SIP/12345-00000016' status is 'UNKNOWN'
-- Executing [h@from-internal:1] Hangup("SIP/12345-00000016", "") in new stack
== Spawn extension (from-internal, h, 1) exited non-zero on 'SIP/12345-00000016'
我看到我在 /var/lib/asterisk/agi-bin 中有这个文件,其中 777 权限。
请建议让这个基本脚本工作。
提前谢谢大家