0

我有以下关于学说的查询:

$q = Doctrine_Query::create()
    ->select("q.id, q.user_id, count(ua.id) as quantity")
    ->from("question q")
    ->leftJoin("q.Answers a")
    ->leftJoin("a.UserAnswers ua")
    ->groupBy("ua.user_id");

生成的 SQL 为:

SELECT q.id AS q__id, q.user_id AS q__user_id, COUNT(u.id) AS u__0 FROM question q LEFT JOIN answer a ON q.id = a.question_id LEFT JOIN user_answer u ON a.id = u.answer_id GROUP BY u.user_id

这个查询在 MySQL 中的结果是这样的:

+-------+------------+------+
+ q__id + q__user_id + u__0 +
+-------+------------+------+
+     1 +          1 +    0 +
+-------+------------+------+
+    26 +          6 +    2 +
+-------+------------+------+
+    26 +          6 +    1 +
+-------+------------+------+

使用 Doctrine,有没有办法获得“u__0”列值?

我试过了:

$questions = $q->execute();
echo (count($questions));

但结果只有 2 行(不是 3 行)。

如何获取“u__0”列值?(0, 2, 1) 使用教义?

4

2 回答 2

2

您必须为每个结果循环并检索quantity值:

$q = Doctrine_Query::create()
    ->select("q.id as id, q.user_id as question_user_id, ua.user_id as answer_user_id, count(ua.id) as quantity")
    ->from("question q")
    ->leftJoin("q.Answers a")
    ->leftJoin("a.UserAnswers ua")
    ->groupBy("answer_user_id");

$results = $q->execute(array(), Doctrine_Core::HYDRATE_ARRAY);
foreach ($results as $result)
{
    var_dump($result['quantity']);
}
于 2013-03-13T15:26:44.340 回答
1

我将 SQL 查询更改为:

$q = Doctrine_Query::create()
    ->select("q.id, q.user_id, a.id, count(ua.id) as quantity")
    ->from("Answer a")
    ->leftJoin("a.Question q")
    ->leftJoin("a.UserAnswers ua")
    ->groupBy("ua.user_id");

它有效;)

于 2013-03-14T18:07:23.323 回答