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所以我对 Java 比较陌生,并尝试使用 JButtons 为棋盘和棋子创建一个跳棋游戏。但是我似乎无法通过 ActionListener 删除 JButton。任何意见,将不胜感激。

    public static void main(String[] args) {
    checkersBeBitchin begin = new checkersBeBitchin();

}

public checkersBeBitchin(){
    box.setLayout(new BorderLayout());
    makeBoard();
    setVisible(true);
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    setLocationRelativeTo(null);
    setSize(600,600);
    setTitle("Checkers");


        }

private void makeBoard() {
    JPanel board = new JPanel();
    board.setLayout(new GridLayout(8,8));
    for (int i=0; i<8; i++){
        for (int j=0; j<8; j++) {
            squares[i][j] = new JButton();
            ActionListener actionListener = new Board();
            squares[i][j].addActionListener(actionListener);
            if((i%2 != 0 && j%2 !=0) ||(i%2==0 && j%2 == 0) ){
                    squares[i][j].setBackground(Color.black);
                    pieceTracker[i][j]=0;
                    //System.out.println("Black"+i+","+j); debugging
                    if(i<3){
                        int blue = 1;
                        Icon piece = new ImageIcon(getClass().getResource("/resources/piece.png"));
                        JButton button = new JButton(piece);
                        //squares[i][j].setRolloverIcon("image dir") to make it prettier down the road.
                        squares[i][j].add(button);
                        pieceTracker[i][j]=blue;
                        ActionListener Listener = new Blue();
                        button.addActionListener(Listener);
                        }
                    else if (i>4){
                        int red=-1;
                        Icon piece = new ImageIcon(getClass().getResource("/resources/piece2.png"));
                        JButton button = new JButton(piece);

                        squares[i][j].add(button);
                        pieceTracker[i][j]=red;
                        ActionListener Listener = new Red();
                        button.addActionListener(Listener);
                        //squares[i][j].setRolloverSelectedIcon("/resources/piece2alt.png");
                        }

            }
            else{
                squares[i][j].setBackground(Color.white);
                pieceTracker[i][j]=0;
                //System.out.println("White"+i+","+j); //debugging
                }
            board.add(squares[i][j]);

            }

        }
    box.add(board, BorderLayout.CENTER);
    }
private class Blue implements ActionListener{


    public void actionPerformed (ActionEvent e){
        System.out.println("You sexy Blue beast.");
        Object x = e.getSource();
        System.err.println(x);
        squares.remove(x);
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1 回答 1

2

方格。删除?它应该读为 squares.remove(x) 吗?我们能看到正方形的定义吗?它是一个数组吗?您必须从板上删除按钮而不是正方形,例如board.remove(x)

于 2013-03-13T14:48:24.600 回答