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下面的 SQL 语句生成一个数据透视表，所有这些都正常工作。但是，在代码的底部，我试图显示另一个表（可用性注释）中的值 - 在下面的这个示例中，注释将是“A/P”。每一天都会有 0 或 1 个音符。当存在注释时，将显示注释。如果不存在注释，则会显示 COALESCE 值。但是，如果在星期一设置了 1 位教师的注释，而在星期三设置了注释，则会返回重复的行。如何将其设置为在一行上返回所有值？

   WITH Bookings AS
(   SELECT  TeacherID,
            [WeekDay] = DATENAME(WEEKDAY, BookingDate),
            [Status] = CASE WHEN [2] > 0 THEN 'XXX'
                            WHEN [0] > 0 AND [1] > 0 THEN 'XXX'
                            WHEN [0] > 0 THEN 'PM'
                            WHEN [1] > 0 THEN 'AM'
                            WHEN [3] > 0 AND CONVERT(time(0), EndTime) <= CONVERT(time(0), '12:00:00') and CONVERT(time(0), StartTime) < CONVERT(time(0), '12:00:00') THEN 'PM'
                            WHEN [3] > 0 AND CONVERT(time(0), StartTime) >= CONVERT(time(0), '12:00:00') THEN 'AM'
                            WHEN [3] > 0 AND CONVERT(time(0), StartTime) <= CONVERT(time(0), '12:00:00') AND CONVERT(time(0), EndTime) >= CONVERT(time(0), '12:00:00') THEN 'XXX'
                        END

    FROM    (   SELECT  TeacherID, BookingDate, BookingDuration, StartTime, EndTime, [X] = 1
                FROM    BookingDays where (Status = 0 or Status IS NULL)
            ) BookingDays
            PIVOT
            (   SUM(X)
                FOR BookingDuration IN ([0], [1], [2], [3])
            ) pvt
             WHERE BookingDate >= DATEADD(ww, DATEDIFF(ww,0,@Date), 0) AND BookingDate <= DATEADD(ww, DATEDIFF(ww,0,@Date), 6)

), PivotedBookings AS
(   SELECT  *
    FROM    Bookings
            PIVOT
            (   MAX([Status])
                FOR [WeekDay] IN ([Monday], [Tuesday], [Wednesday], [Thursday], [Friday])
            ) pvt

)
SELECT  t.ID, 
        t.Firstname, 
        t.Surname, 
        CASE WHEN t.Nursery > 0 THEN 'NUR' WHEN t.Reception > 0 THEN 'REC' WHEN t.Year1 > 0 THEN 'Y1' WHEN t.Year2 > 0 THEN 'Y2' WHEN t.Year3 > 0 THEN 'Y3' WHEN t.Year4 > 0 THEN 'Y4' WHEN t.Year5 > 0 THEN 'Y5' WHEN t.Year6 > 0 THEN 'Y6' WHEN t.Year7 > 0 THEN 'Y7' WHEN t.Year8 > 0 THEN 'Y8' WHEN t.Year9 > 0 THEN 'Y9' WHEN t.Year10 > 0 THEN 'Y10' WHEN t.Year11 > 0 THEN 'Y11' WHEN t.ALevel > 0 THEN 'ALevel' END + ' - ' + CASE WHEN t.ALevel > 0 THEN 'ALevel' WHEN t.Year11 > 0 THEN 'Y11' WHEN t.Year10 > 0 THEN 'Y10' WHEN t.Year9 > 0 THEN 'Y9' WHEN t.Year8 > 0 THEN 'Y7' WHEN t.Year6 > 0 THEN 'Y6' WHEN t.Year5 > 0 THEN 'Y6' WHEN t.Year4 > 0 THEN 'Y4' WHEN t.Year3 > 0 THEN 'Y3' WHEN t.Year2 > 0 THEN 'Y2' WHEN t.Year1 > 0 THEN 'Y1' WHEN t.Reception > 0 THEN 'REC' WHEN t.Nursery > 0 THEN 'NUR' ELSE '' END as 'KeyStage',

        Monday = CASE WHEN an.Date = DATEADD(ww, DATEDIFF(ww,0,@Date), 0) AND an.TeacherID = t.ID THEN an.Text WHEN t.Status = 0 THEN 'XXX'  ELSE COALESCE(pb.Monday, '') END,
        Tuesday = CASE WHEN an.Date = DATEADD(ww, DATEDIFF(ww,0,@Date), 1) AND an.TeacherID = t.ID THEN an.Text WHEN t.Status = 0 THEN 'XXX'  ELSE COALESCE(pb.Tuesday, '') END,
        Wednesday = CASE WHEN an.Date = DATEADD(ww, DATEDIFF(ww,0,@Date), 2) AND an.TeacherID = t.ID THEN an.Text WHEN t.Status = 0 THEN 'XXX'  ELSE COALESCE(pb.Wednesday, '') END,
        Thursday = CASE WHEN an.Date = DATEADD(ww, DATEDIFF(ww,0,@Date), 3) AND an.TeacherID = t.ID THEN an.Text WHEN t.Status = 0 THEN 'XXX'  ELSE COALESCE(pb.Thursday, '') END,
        Friday = CASE WHEN an.Date = DATEADD(ww, DATEDIFF(ww,0,@Date), 4) AND an.TeacherID = t.ID THEN an.Text WHEN t.Status = 0 THEN 'XXX'  ELSE COALESCE(pb.Friday, '') END
FROM    Teachers t

        LEFT JOIN PivotedBookings pb
            ON pb.TeacherID = t.ID
        LEFT JOIN TeacherBands tb
            ON tb.ID = t.Band
        LEFT JOIN AvailabilityNotes an 
            ON t.ID = an.TeacherID
            WHERE t.Active = 0 and (t.Status = 1 or t.Status = 0) and t.PrimarySchool = 1
            ORDER BY t.Surname, t.Firstname asc

这会生成以下输出 -

ID | Firstname | Surname | Mon | Tue | Wed | Thu | Fri 
1    Steve       Smith     XXX   PM    AM    A/P   NULL   
1    Steve       Smith     XXX   PM    AM    NULL   A/P

当我需要它时——

ID | Firstname | Surname | Mon | Tue | Wed | Thu | Fri 
1    Steve       Smith     XXX   PM    AM    A/P   A/P

谢谢

4

1 回答 1

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您需要每天的有效值，如果存在，它将大于 NULL。

select   ID, Firstname, Surname
       , max(Monday) as Monday, -- etc
from ( your giant query ) as Q
group by ID, Firstname, Surname

应该做的伎俩。

于 2013-03-14T03:26:10.883 回答