java - 压缩 zip 存档

Question

我正在尝试使用 java 将目录内容压缩到 zip 存档中。一切都很好，但我只想澄清一些事实。这是我用来压缩文件的代码：

public void pack(@Nonnull String archiveName, @Nonnull File outputDir, @Nonnull File targetDir) {
  File zipFile = new File(outputDir, "out.zip");

  ZipOutputStream zipOutputStream = null;
  OutputStream outputStream;
  try {
    // create stream for writing zip archive
    outputStream = new FileOutputStream(zipFile);
    zipOutputStream = new ZipOutputStream(outputStream);
    // write files recursively
    writeFiles(zipOutputStream, targetDir.listFiles(), "");
  } catch (IOException e) {
    LOGGER.error("IO exception while packing files to archive", e);
  } finally {
    // close output streams
    if (zipOutputStream != null) {
      try {
        zipOutputStream.close();
      } catch (IOException e) {
        LOGGER.error("Unable to close zip output stream", e);
      }
    }
  }
}

/**
 * Writes specified files and their children (in case of directories) to archive
 *
 * @param zipOutputStream archive output stream
 * @param files           which should be added to archive
 * @param path            path relative of root of archive where files should be placed
 */
private void writeFiles(@Nonnull ZipOutputStream zipOutputStream, @Nullable File[] files, @Nonnull String path) throws IOException {
  if (files == null || files.length == 0) {
    return;
  }

  for (File file : files) {
    if (file.isDirectory()) {
      // recursively add files in this directory
      String fullDirectoryName = path + file.getName() + "/";
      File[] childFiles = file.listFiles();
      if (childFiles != null && childFiles.length > 0) {
        // write child files to archive. current directory will be created automatically
        writeFiles(zipOutputStream, childFiles, fullDirectoryName);
      } else {
        // empty directory. write directory itself to archive
        ZipEntry entry = new ZipEntry(fullDirectoryName);
        zipOutputStream.putNextEntry(entry);
        zipOutputStream.closeEntry();
      }
    } else {
      // put file in archive
      BufferedInputStream bufferedInputStream = new BufferedInputStream(new FileInputStream(file));
      zipOutputStream.putNextEntry(new ZipEntry(path + file.getName()));
      ByteStreams.copy(bufferedInputStream, zipOutputStream);
      zipOutputStream.closeEntry();
      bufferedInputStream.close();
    }
  }
}

现在有问题：

1. 默认情况下（在我的情况下也是如此）我将获得已经压缩的存档（使用 Deflate 方法）是否正确？

2. 如何获取未压缩的存档：

   • 如果我设置方法zipOutputStream.setMethod(ZipOutputStream.STORED)我必须提供大小、压缩大小（它会等于大小吗？）和 crc，否则我会得到异常
   • 如果我不想自己计算大小和 crc，我可以使用DEFLATE零级别的方法：

     zipOutputStream.setMethod(ZipOutputStream.DEFLATED);
     zipOutputStream.setLevel(ZipOutputStream.STORED);

     那么，在这种情况下我根本没有压缩存档是否正确？
   • 有没有更方便、更直观的方法来创建非压缩档案？

Answer 1

Rather than re-invent the wheel I'd seriously consider using an existing library for this, such as Apache Ant. The basic idiom for creating a zip file is:

Project p = new Project();
p.init();
Zip zip = new Zip();
zip.setProject(p);
zip.setDestFile(new File(outputDir, "out.zip"));
FileSet fs = new FileSet();
fs.setProject(p);
fs.setDirectory(targetDir);
zip.addFileset(fs);
zip.perform();

By default you will get a compressed archive. For an uncompressed zip all you need to add is

zip.setCompress(false);

after the setDestFile (in fact anywhere before the perform).