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我有一个要使用 boost 序列化程序保存和加载的数据类。

该类包括两个成员En *sender，En *receiver两个对象已在我的系统中创建。我不需要再次创建它们。我只需要发送（序列化）它们的address, 以用作另一端的参考。

En *sender如果我使用像,这样的普通指针 En *receiver，boost 将序列化整个对象（我不想要）。

所以我想我应该使用En **sender，En **receiver 这会产生错误。我可以知道我应该如何修改课程以达到我的目的吗？

非常感谢。

class dataMessage
{

    friend class boost::serialization::access;
    template<class Archive>
    void serialize(Archive &ar, const unsigned int version)
    {            
        ar & sender;
        ar & receiver;
    }
    //I figured I should user pointer to pointer coz in case of the normal pointer,
    //the serilizer would serializes the object that the pointer is pointing to;
    //whereas I just need to save the 'pointer' to object so that we
    //can use it as a reference at the other end.
    En **sender;
    En **receiver;
public:
    dataMessage(){
        sender = receiver = 0;
    }
    void setDataClassType();
    virtual void registerType(boost::archive::text_oarchive &oa)
    {
        oa.register_type(static_cast<dataMessage *>(NULL));
    }

    virtual void registerType(boost::archive::text_iarchive &ia)
    {
        ia.register_type(static_cast<dataMessage *>(NULL));
    }
};

部分错误：

error: request for member ‘serialize’ in ‘t’, which is of pointer type ‘En*’ (maybe you meant to use ‘->’ ?)
4

1 回答 1

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似乎没有办法手动存储地址，否则 boostserializer 将序列化目标对象。所以我将发送者接收者类型修改为：

class dataMessage
{

 //......
public:
//.....
    //a proper size of integer is used coz in case of the normal pointer,
    //the serilizer serializes the object that the pointer is pointing to
    //whereas we just need to save the 'pointer' to object so that we
    //can use it as a reference at the other end. so instead of storing 'sim_mob::Entity *'
    //we store:
#if __x86_64__  //64 bit
    unsigned long sender;
    unsigned long receiver;
#else          //32 bit
    unsigned int sender;
    unsigned int receiver;

#endif


    dataMessage(){
        sender = receiver = 0;
    }
//...
};

稍后在使用指针时，我将对适当的指针类型进行简单的转换。

于 2013-03-13T10:15:30.713 回答