首先,创建一个 Split 函数,它返回一个整数和一个保持顺序的序列号。这是一个例子:
ALTER FUNCTION dbo.SplitInts
(
@List VARCHAR(MAX),
@Delimiter VARCHAR(32)
)
RETURNS TABLE
AS
RETURN
(
SELECT rn = ROW_NUMBER() OVER (ORDER BY Number),
Item = CONVERT(INT, Item)
FROM (SELECT Number, Item = LTRIM(RTRIM(SUBSTRING(@List, Number,
CHARINDEX(@Delimiter, @List + @Delimiter, Number) - Number)))
FROM (SELECT ROW_NUMBER() OVER (ORDER BY [object_id])
FROM sys.all_objects) AS n(Number)
WHERE Number <= CONVERT(INT, LEN(@List))
AND SUBSTRING(@Delimiter + @List, Number, 1) = @Delimiter
) AS y
);
GO
然后以下查询执行您所追求的:
DECLARE @t1 TABLE
(
Item VARCHAR(MAX),
[Date] DATE -- terrible column name!
);
INSERT @t1 VALUES('1;4;5;','20130313'),('1;2;3;','20130313');
-- please use unambiguous date formats!
DECLARE @t2 TABLE
(
ID INT, -- another bad column name - what kind of ID?
[Desc] VARCHAR(255) -- another bad column name, this is a keyword!
);
INSERT @t2 VALUES(1,'Tree'),(2,'Grass'),
(3,'Sand'),(4,'Water'),(5,'Bridge');
;WITH x AS
(
SELECT t1.Item, Date, t2ID = i.Item, i.rn, n = t2.[Desc]
FROM @t1 AS t1 CROSS APPLY dbo.SplitInts(t1.Item, ';') AS i
INNER JOIN @t2 AS t2 ON i.Item = t2.ID
)
SELECT DISTINCT Item = (
SELECT n + ';' FROM x AS x2
WHERE x.Item = x2.Item
ORDER BY x2.rn FOR XML PATH,
TYPE).value(N'./type()[1]', N'varchar(max)'), [Date]
FROM x;
强烈建议您研究标准化。分号分隔的列表是一种将独立值组合在一起的糟糕方式。