我们将 XML 数据作为名为 XML 的单个字符串列加载到 Hadoop 中。我们正在尝试检索数据级别并进行规范化或将其分解为单行以进行处理(您知道,就像一个表格!)尝试了分解功能,但没有得到我们想要的。
示例 XML
<Reports>
<Report ID="1">
<Locations>
<Location ID="20001">
<LocationName>Irvine Animal Shelter</LocationName>
</Location>
<Location ID="20002">
<LocationName>Irvine City Hall</LocationName>
</Location>
</Locations>
</Report>
<Report ID="2">
<Locations>
<Location ID="10001">
<LocationName>California Fish Grill</LocationName>
</Location>
<Location ID="10002">
<LocationName>Fukada</LocationName>
</Location>
</Locations>
</Report>
</Reports>
查询 1
我们正在查询更高级别的 Report.Id,然后是子级的 id 和名称(Locations/Location)。下面给了我们所有可能组合的基本笛卡尔积(在这个例子中,8 行而不是我们希望的 4 行。)
SELECT xpath_int(xml, '/Reports/Report/@ID') AS id, location_id, location_name
FROM xmlreports
LATERAL VIEW explode(xpath(xml, '/Reports/Report/Locations/Location/@ID')) myTable1 AS location_id
LATERAL VIEW explode(xpath(xml, '/Reports/Report/Locations/Location/LocationName/text()')) myTable2 AS location_name;
查询 2
试图组合成一个结构然后分解,但这会返回两行和两个数组。
SELECT id, loc.col1, loc.col2
FROM (
SELECT xpath_int(xml, '/Reports/Report/@ID') AS id,
array(struct(xpath(xml, '/Reports/Report/Locations/Location/@ID'), xpath(xml, '/Reports/Report/Locations/Location/LocationName/text()'))) As foo
FROM xmlreports) x
LATERAL VIEW explode(foo) exploded_table as loc;
结果
1 ["20001","20002"] ["Irvine Animal Shelter","Irvine City Hall"]
2 ["10001","10002"] ["California Fish Grill","Irvine Spectrum"]
我们想要的是什么
1 "20001" "Irvine Animal Shelter"
1 "20002" "Irvine City Hall"
2 "10001" "California Fish Grill"
2 "10002" "Irvine Spectrum"
似乎是一件很常见的事情,但找不到任何例子。任何帮助是极大的赞赏。