xml - Scala XML 节点（带有命名空间）属性不可访问

Question

嗨，

我正在尝试从此 XML Node/Elem 获取 attrID。

scala> (desc(0) \ "_")(0)
res81: scala.xml.Node = <cor:attribute cor:attrDataType="int" cor:attrID="singleEventID"    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:cor="http://rdm.campusonline.at/">883819995</cor:attribute>

scala> (desc(0) \ "_")(0).attributes
res82: scala.xml.MetaData =  cor:attrDataType="int" cor:attrID="singleEventID"

scala> (desc(0) \ "_")(0).attribute("cor:attrID")
res83: Option[Seq[scala.xml.Node]] = None

scala> (desc(0) \ "_")(0).attribute("""attrID""")
res85: Option[Seq[scala.xml.Node]] = None

如果我手动删除命名空间，它工作得很好。

scala> val test4 = <attribute attrDataType="int" attrID="singleEventID" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:cor="http://rdm.campusonline.at/">883819995</attribute>
test4: scala.xml.Elem = <attribute attrID="singleEventID" attrDataType="int" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:cor="http://rdm.campusonline.at/">883819995</attribute>

scala> test4.attributes
res96: scala.xml.MetaData =  attrID="singleEventID" attrDataType="int"

scala> test4.attribute("attrID")
res98: Option[Seq[scala.xml.Node]] = Some(singleEventID)

我如何在不手动删除命名空间的情况下使其工作？

Answer 1

您需要attribute像这样使用其他方法

(desc(0) \ "_")(0).attribute("http://rdm.campusonline.at/", "attrID")

Answer 2

此解决方案将为您提供字符串形式的属性

val CoreNs = http://rdm.campusonline.at
(desc(0) \ "_") \@ s"{$CoreNs}:attrID"