42

I have also tried searching for the answer but I don't understand the answers to other people's similar problems...

tfile= open("/home/path/to/file",'r') 

def temp_sky(lreq, breq):
    for line in tfile:
        data = line.split()
        if (    abs(float(data[0]) - lreq) <= 0.1 
            and abs(float(data[1]) - breq) <= 0.1):            
            T= data[2]
    return T
print temp_sky(60, 60)
print temp_sky(10, -10)

I get the following error 

7.37052488
Traceback (most recent call last):
File "tsky.py", line 25, in <module>
  print temp_sky(10, -10)
File "tsky.py", line 22, in temp_sky
  return T
UnboundLocalError: local variable 'T' referenced before assignment

The first print statement works correctly but it won't work for the second. I have tried making T a global variable but this makes both answers the same! Please help!

4

7 回答 7

40

Your if statement is always false and T gets initialized only if a condition is met, so the code doesn't reach the point where T gets a value (and by that, gets defined/bound). You should introduce the variable in a place that always gets executed.

Try:

def temp_sky(lreq, breq):
    T = <some_default_value> # None is often a good pick
    for line in tfile:
        data = line.split()
        if abs(float(data[0])-lreq) <= 0.1 and abs(float(data[1])-breq) <= 0.1:
            T = data[2]
    return T
于 2013-03-12T17:17:00.113 回答
9

FWIW: I got the same error for a different reason. I post the answer here not for the benefit of the OP, but for the benefit of those who may end up on this page due to its title... who might have made the same mistake I did.

I was confused why I was getting "local variable referenced before assignment" because I was calling a FUNCTION that I knew was already defined:

def job_fn(job):
  return job + ".job"

def do_something():
  a = 1
  b = 2
  job_fn = job_fn("foo")

do_something()

This was giving:

UnboundLocalError: local variable 'job_fn' referenced before assignment

Took me a while to see my obvious problem: I used a local variable named job_fn which masked the ability to see the prior function definition for job_fn.

于 2014-11-24T19:33:42.770 回答
5

The other answers are correct: You don't have a default value. However, you have another problem in your logic:

You read the same file twice. After reading it once, the cursor is at the end of the file, so trying to read it again returns nothing and the loop is never entered. To solve this, you can do two things: Either open/close the file upon each function call:

def temp_sky(lreq, breq):
    with open("/home/path/to/file",'r') as tfile:
        # do your stuff

This has the disadvantage of having to open the file each time. The better way would be:

tfile.seek(0)

You do this after your for line in tfile: loop. It resets the cursor to the beginning so the next call will start from there again.

Related questions:

于 2013-03-12T17:37:57.323 回答
1

Before I start, I'd like to note that I can't actually test this since your script reads data from a file that I don't have.

'T' is defined in a local scope for the declared function. In the first instance 'T' is assigned the value of 'data[2]' because the conditional statement above apparently evaluates to True. Since the second call to the function causes the 'UnboundLocalError' exception to occur, the local variable 'T' is getting set and the conditional assignment is never getting triggered.

Since you appear to want to return the first bit of data in the file that matches your conditonal statement, you might want to modify you function to look like this:

def temp_sky(lreq, breq):
    for line in tfile:
        data = line.split()
        if ( abs(float(data[0]) - lreq) <= 0.1 and abs(float(data[1]) - breq) <= 0.1):            
            return data[2]
    return None

That way the desired value gets returned when it is found, and 'None' is returned when no matching data is found.

于 2013-03-12T17:28:32.827 回答
0

I was facing same issue in my exercise. Although not related, yet might give some reference. I didn't get any error once I placed addition_result = 0 inside function. Hope it helps! Apologize if this answer is not in context.

user_input = input("Enter multiple values separated by comma > ")

def add_numbers(num_list):
    addition_result = 0
    for i in num_list:
        addition_result = addition_result + i
    print(addition_result)

add_numbers(user_input)
于 2015-05-11T04:26:17.463 回答
0

Contributing to ferrix example, 

class Battery():

    def __init__(self, battery_size = 60):
        self.battery_size = battery_size
    def get_range(self):
        if self.battery_size == 70:
            range = 240
        elif self.battery_size == 85:
        range = 270

        message = "This car can go approx " + str(range)
        message += "Fully charge"
        print(message)

My message will not execute, because none of my conditions are fulfill therefore receiving " UnboundLocalError: local variable 'range' referenced before assignment" 

def get_range(self):
    if self.battery_size <= 70:
        range = 240
    elif self.battery_size >= 85:
        range = 270
于 2016-01-19T01:23:55.230 回答
-1

To Solve this Error just initialize that variable above that loop or statement. For Example var a =""

于 2017-03-03T04:40:14.067 回答