mysql - 如何使用联合所有查询来获取不在表中的记录？

Question

我在 MYSQL 数据库中有 a_ad_display 表，格式如下

╔═════════════╦═════════╦═════════╦═════════════════════╗
║ addisplayId ║ restId  ║ clicked ║     displaytime     ║
╠═════════════╬═════════╬═════════╬═════════════════════╣
║          1  ║  20707  ║      0  ║ 2013-03-07 10:50:55 ║
║          2  ║  20707  ║      1  ║ 2013-03-07 10:55:55 ║
║          3  ║  20711  ║      1  ║ 2013-03-08 12:50:55 ║
║          4  ║  20712  ║      1  ║ 2013-03-08 01:50:55 ║
║          5  ║  20707  ║      1  ║ 2013-03-08 10:50:55 ║
║          6  ║  20708  ║      1  ║ 2013-03-09 12:50:55 ║
║          7  ║  20707  ║      1  ║ 2013-03-09 09:50:55 ║
║          8  ║  20708  ║      0  ║ 2013-03-10 10:50:55 ║
║          9  ║  20708  ║      0  ║ 2013-03-11 11:50:55 ║
║         10  ║  20707  ║      0  ║ 2013-03-11 12:50:55 ║
╚═════════════╩═════════╩═════════╩═════════════════════╝

现在我想要的是用过去 7 天的数据获取 restId 的记录

如果当前日期是 2013-3-12 那么我想显示 2013-3-5 到 2013-3-11 的数据

     DISPLAY TIME                   CLICKED     count of row(impression)
March, 05 2013 00:00:00+0000            0       0             
March, 06 2013 00:00:00+0000            0       0
March, 07 2013 00:00:00+0000            1       2
March, 08 2013 00:00:00+0000            1       1
March, 09 2013 00:00:00+0000            1       1
March, 10 2013 00:00:00+0000            1       1
March, 11 2013 00:00:00+0000            0       1

我想忽略时间..只想在明智地获取记录的同时关注日期表中没有针对上周日期出现的任何日期的记录，那么它应该打印该日期并在单击时打印 0，并且在行计数列中打印 0。

我在 SQL fiddle 中制作了一个虚拟表，也应用了这个查询，但它不起作用..所以任何人都可以请指导我...我知道它很难理解..但是如果您对我的问题有任何疑问..那么将清除你从你身边得到一个解决方案..

以下是我的查询，它没有提供正确的数据

select
  displaytime,
  sum(impression) as clicked,
  (count(impression) -1) as impressions
from (
  select
    displaytime,
    a_ad_display.clicked as impression
  from
    a_ad_display
  where
    a_ad_display.displaytime
  BETWEEN
    date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -6 day)
    AND
    CONVERT_TZ(CURDATE( ),'+00:00','-11:00')
    and
    restId=10708
    group by
      a_ad_display.displaytime
    union distinct
    select
      CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), 0
    union distinct
    select
      date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -1 day), 0
    union distinct
    select
      date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -2 day), 0
    union distinct
    select
      date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -3 day), 0
    union distinct
    select
      date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -4 day), 0
    union distinct
    select
      date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -5 day), 0
    union distinct
    select
      date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -6 day), 0
) as x
group by
  date(displaytime)
order by
  displaytime

请忽略该代码， CONVERT_TZ(CURDATE( ),'+00:00','-11:00')因为它只是将我的日期从UTC转换为用户时区...

这是我的 sql fiddle 链接 http://sqlfiddle.com/#!2/73f07/1

score 2 · Accepted Answer

此查询应显示正确的数据。不是一个非常“干净”的解决方案。如果您真的想包含没有数据的日期，您应该用日历表替换这些联合。

SELECT IFNULL(z.displaytime, x.displaytime), IFNULL(z.clicked, 0), IFNULL(z.count, 0)  FROM

  (select
    date(CONVERT_TZ(CURDATE( ),'+00:00','-11:00')) AS 'displaytime', 0 AS 'Clicked', 0 AS 'count of row(impression)'
  union distinct
  select
    date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -1 day)), 0, 0
  union distinct
  select
    date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -2 day)), 0, 0
  union distinct
  select
    date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -3 day)), 0, 0
  union distinct
  select
    date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -4 day)), 0, 0
  union distinct
  select
    date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -5 day)), 0, 0
  union distinct
  select
    date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -6 day)), 0, 0) AS x

LEFT JOIN

  (SELECT
    DATE(displaytime) AS 'displaytime',
    MAX(clicked) AS 'Clicked',
    COUNT(*) AS 'Count'
  FROM 
    a_ad_display
  WHERE (
    displaytime BETWEEN date_add(CURDATE(), interval -6 day) AND CURDATE()
  ) AND restId = 10707 
  GROUP BY DATE(displaytime)) AS z
ON x.displaytime = z.displaytime

score 1 · Accepted Answer

可能有一种更清洁的方法，但这应该可以......

select
  displaytime,
  sum(clicked) as clicked,
  sum(impressions) as impressions
from (
select
  displaytime,
  clicked,
  impressions
from (
select
  date(displaytime) as displaytime,
  sum(impression) as clicked,
  sum(legit) as impressions
from (
  select
    displaytime,
    a_ad_display.clicked as impression,
  1 as legit
  from
    a_ad_display
  where
    a_ad_display.displaytime
  BETWEEN
    date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -6 day)
    AND
    CONVERT_TZ(CURDATE( ),'+00:00','-11:00')
    and
    restId=10708
) as x
group by
  date(displaytime)
) y
union distinct
    select
      date(CONVERT_TZ(CURDATE( ),'+00:00','-11:00')), 0, 0
    union distinct
    select
      date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -1 day)), 0, 0
    union distinct
    select
      date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -2 day)), 0, 0
    union distinct
    select
      date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -3 day)), 0, 0
    union distinct
    select
      date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -4 day)), 0, 0
    union distinct
    select
      date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -5 day)), 0, 0
    union distinct
    select
      date(date_add(CONVERT_TZ(CURDATE( ),'+00:00','-11:00'), interval -6 day)), 0, 0
) z
group by
  displaytime
order by
  displaytime

score 1 · Accepted Answer

其他一些解决方案restID 20707。2013-03-10 没有restID 20707.

查询SQLFIDDLE 示例：

SELECT d.Date,
(SELECT CASE WHEN COUNT(clicked) >0 THEN 1 ELSE 0 END
FROM a_ad_display
WHERE DATE(displaytime) = d.Date 
AND clicked = 1
AND restId  = 20707  ) Clicked,
(SELECT COUNT(*)
FROM a_ad_display
WHERE DATE(displaytime) = d.Date 
AND restId  = 20707  ) 'count of row'
FROM 
(SELECT a.Date
FROM
  (SELECT curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY AS Date
   FROM
     (SELECT 0 AS a
      UNION ALL SELECT 1
      UNION ALL SELECT 2
      UNION ALL SELECT 3
      UNION ALL SELECT 4
      UNION ALL SELECT 5
      UNION ALL SELECT 6
      UNION ALL SELECT 7
      UNION ALL SELECT 8
      UNION ALL SELECT 9) AS a CROSS
   JOIN
     (SELECT 0 AS a
      UNION ALL SELECT 1
      UNION ALL SELECT 2
      UNION ALL SELECT 3
      UNION ALL SELECT 4
      UNION ALL SELECT 5
      UNION ALL SELECT 6
      UNION ALL SELECT 7
      UNION ALL SELECT 8
      UNION ALL SELECT 9) AS b CROSS
   JOIN
     (SELECT 0 AS a
      UNION ALL SELECT 1
      UNION ALL SELECT 2
      UNION ALL SELECT 3
      UNION ALL SELECT 4
      UNION ALL SELECT 5
      UNION ALL SELECT 6
      UNION ALL SELECT 7
      UNION ALL SELECT 8
      UNION ALL SELECT 9) AS c) a
where a.Date >= '2013-01-01' and a.Date < curdate()) d
WHERE d.Date >= date_add(curdate(), INTERVAL -7 DAY)
ORDER BY d.Date

结果：

|                         DATE | CLICKED | COUNT OF ROW |
---------------------------------------------------------
| March, 05 2013 00:00:00+0000 |       0 |            0 |
| March, 06 2013 00:00:00+0000 |       0 |            0 |
| March, 07 2013 00:00:00+0000 |       1 |            2 |
| March, 08 2013 00:00:00+0000 |       1 |            1 |
| March, 09 2013 00:00:00+0000 |       1 |            1 |
| March, 10 2013 00:00:00+0000 |       0 |            0 |
| March, 11 2013 00:00:00+0000 |       0 |            1 |

score 0 · Accepted Answer

0

看看这个问题：

过去 5 天按天分组

它几乎和你正在做的一样

于 2013-03-12T06:14:30.883 回答

mysql - 如何使用联合所有查询来获取不在表中的记录？

4 回答 4

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