在 C# 3.5 及更早版本中,最好的办法是简单地使用一大堆属性。
然而,在 C# 4.0 中,您可以使用dynamic
类型和子类DynamicObject
来获得您正在寻找的功能。这可能是也可能不是更好的选择,我不太了解此功能。
编辑:
我对这个问题很感兴趣,所以我去实现了一个 C# 4.0 解决方案。代码如下,但你也可以下载完整的解决方案,如果这更适合你[ github ]。与往常一样,您可以随意使用/破坏/制作此代码,如果它会擦除您的硬盘驱动器,请不要怪我。
编辑 3:
这是我将在这里进行的最后一次编辑,但我可能会更多地使用它,并且我会为以后来到这里的任何人保持最新的链接版本。
编辑2:
Program.Main()
在我让您了解代码之前,有一些示例说明了代码本身可以做什么和不可以做什么。
现在,进入代码。
namespace Swizzle
{
/// <summary>
/// This implements the Vector4 class as described in the question, based on our totally generic
/// Vector class.
/// </summary>
class Vector4 : Vector<int>
{
public Vector4(int val0, int val1, int val2, int val3)
: base(new Dictionary<char, int> { {'t', 0}, {'x', 1}, {'y', 2}, {'z', 3},
{'a', 0}, {'r', 1}, {'g', 2}, {'b', 3}},
new int[] { val0, val1, val2, val3 })
{ }
}
class Program
{
static void Main(string[] args)
{
dynamic v1, v2, v3;
v1 = new Vector4(1, 2, 3, 4);
v2 = v1.rgb;
// Prints: v2.r: 2
Console.WriteLine("v2.r: {0}", v2.r);
// Prints: red: 2
int red = v2.r;
Console.WriteLine("red: {0}", red);
// Prints: v2 has 3 elements.
Console.WriteLine("v2 has {0} elements.", v2.Length);
v3 = new Vector4(5, 6, 7, 8);
v3.ar = v2.gb; // yes, the names are preserved! v3 = (3, 4, 7, 8)
v2.r = 5;
//v2.a = 5; // fails: v2 has no 'a' element, only 'r', 'g', and 'b'
// Something fun that will also work
Console.WriteLine("v3.gr: {0}", v3.gr);
v3.rg = v3.gr; // switch green and red
Console.WriteLine("v3.gr: {0}", v3.gr);
Console.WriteLine("\r\nPress any key to continue.");
Console.ReadKey(true);
}
}
class Vector<T> : DynamicObject
{
private T[] m_values;
private Dictionary<char, int> m_positions;
public Vector(Dictionary<char, int> positions, params T[] values)
{
this.m_positions = positions;
this.m_values = values;
}
public T this[int index] {
get { return this.m_values[index]; }
}
public int Length
{
get { return this.m_values.Length; }
}
public override string ToString()
{
List<string> elements = new List<string>(this.Length);
for (int i = 0; i < this.Length; i++)
{
elements.Add(m_values[i].ToString());
}
return string.Join(", ", elements.ToArray());
}
public override bool TryGetMember(GetMemberBinder binder, out object result)
{
if (binder.Name == "Length") {
result = this.Length;
return true;
}
if (binder.Name.Length == 1 && this.m_positions.ContainsKey(binder.Name[0]))
{
result = m_values[this.m_positions[binder.Name[0]]];
return true;
}
Dictionary<char, int> positions = new Dictionary<char, int>(binder.Name.Length);
List<T> values = new List<T>(binder.Name.Length);
int i = 0;
foreach (char c in binder.Name)
{
if (!this.m_positions.ContainsKey(c))
return base.TryGetMember(binder, out result);
values.Add(m_values[m_positions[c]]);
positions.Add(c, i);
i++;
}
result = new Vector<T>(positions, values.ToArray());
return true;
}
public override bool TrySetMember(SetMemberBinder binder, object value)
{
// sanity checking.
foreach (char c in binder.Name)
{
if (!this.m_positions.ContainsKey(c))
return base.TrySetMember(binder, value);
}
Vector<T> vectorValue = value as Vector<T>;
if (vectorValue == null && binder.Name.Length == 1 && value is T)
{
m_values[m_positions[binder.Name[0]]] = (T)value;
return true;
}
else if (vectorValue == null)
throw new ArgumentException("You may only set properties of a Vector to another Vector of the same type.");
if (vectorValue.Length != binder.Name.Length)
throw new ArgumentOutOfRangeException("The length of the Vector given does not match the length of the Vector to assign it to.");
int i = 0;
foreach (char c in binder.Name)
{
m_values[m_positions[c]] = vectorValue[i];
i++;
}
return true;
}
}
}