4

我正在尝试在 android 的列表视图中从 url 加载图像。我正在使用下面的代码来做到这一点。

        Bitmap bm;
        try {
            URL url = new URL(imageUrl);
            bm = BitmapFactory.decodeStream(url.openConnection().getInputStream());
        } catch (Exception e) {
            Log.e("Error", e.getMessage());
            e.printStackTrace();
        }
        imageView.setImageBitmap(bm);

我在 AsyncTask 中执行上述代码。当我执行时，它显示正确。但是在我转移到另一个活动并回来之后，图像没有显示。当时我的logcat显示，

W/System.err(3570): java.io.IOException: BufferedInputStream is closed
W/System.err(3570):     at java.io.BufferedInputStream.streamClosed(BufferedInputStream.java:116)
W/System.err(3570):     at java.io.BufferedInputStream.read(BufferedInputStream.java:274)
W/System.err(3570):     at org.apache.harmony.luni.internal.net.www.protocol.http.UnknownLengthHttpInputStream.read(UnknownLengthHttpInputStream.java:40)
W/System.err(3570):     at java.io.BufferedInputStream.fillbuf(BufferedInputStream.java:166)
W/System.err(3570):     at java.io.BufferedInputStream.read(BufferedInputStream.java:324)
W/System.err(3570):     at android.graphics.BitmapFactory.nativeDecodeStream(Native Method)
W/System.err(3570):     at android.graphics.BitmapFactory.decodeStream(BitmapFactory.java:573)
W/System.err(3570):     at android.graphics.BitmapFactory.decodeStream(BitmapFactory.java:628)
W/System.err(3570):     at android.os.AsyncTask$2.call(AsyncTask.java:185)
W/System.err(3570):     at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:306)
W/System.err(3570):     at java.util.concurrent.FutureTask.run(FutureTask.java:138)
W/System.err(3570):     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1088)
W/System.err(3570):     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:581)
W/System.err(3570):     at java.lang.Thread.run(Thread.java:1019)

实际上错误显示在下面的行中，

bm = BitmapFactory.decodeStream(url.openConnection().getInputStream());

我已经在 SO 中搜索并找到与此相关的不同帖子，但找不到任何解决方案......有人可以帮助我吗？

4

4 回答 4

2

试试 Google 的 Jess 的这个解决方法：

修复代码：

/**
 * This input stream won't read() after the underlying stream is exhausted.
 * http://code.google.com/p/android/issues/detail?id=14562
 */
final class DoneHandlerInputStream extends FilterInputStream {
    private boolean done;

    public DoneHandlerInputStream(InputStream stream) {
        super(stream);
    }

    @Override public int read(byte[] bytes, int offset, int count) throws IOException {
        if (!done) {
            int result = super.read(bytes, offset, count);
            if (result != -1) {
                return result;
            }
        }
        done = true;
        return -1;
    }
}

要使用，将从 getInputStream() 返回的流包装在 DoneHandlerInputStream 中：

   InputStream stream = url.openConnection().getInputStream();
   stream = new DoneHandlerInputStream(stream);

   bm = BitmapFactory.decodeStream(stream);
   //rest of your code

查看完整说明： http ://code.google.com/p/android/issues/detail?id=14562

于 2013-04-26T14:34:43.673 回答
0

尝试

URL url = new URL(url);
private Bitmap getBitmap(String url) {  

try {

    Bitmap bm = null;

    bm = BitmapFactory.decodeStream(url.openConnection().getInputStream());
    return bitmap;

} catch (Exception e) {
    Log.e("Error", e.getMessage());
    e.printStackTrace();
   }

}
imageView.setImageBitmap(getBitmap.url);
于 2013-03-11T14:00:10.083 回答
0 
    try {
        is = conn.getInputStream();
        BufferedInputStream bis = new BufferedInputStream(is);
        bm = BitmapFactory.decodeStream(bis);
            is.close();//add
        conn.disconnect();//add
    } catch (IOException e) {
        e.printStackTrace();
    }
于 2013-03-11T15:17:46.143 回答
0

您可能正在使用http url访问http端点

于 2017-09-28T11:00:13.493 回答