我正在尝试计算价格的中位数。我在这里找到了如何做的答案-使用 MySQL 计算中位数的简单方法,但它对我不起作用,我得到空结果。任何人都可以帮忙吗?
SELECT x.price from mediana as x, mediana y
GROUP BY x.price
HAVING SUM(SIGN(1-SIGN(y.price-x.price))) = (COUNT(*)+1)/2
我正在尝试计算价格的中位数。我在这里找到了如何做的答案-使用 MySQL 计算中位数的简单方法,但它对我不起作用,我得到空结果。任何人都可以帮忙吗?
SELECT x.price from mediana as x, mediana y
GROUP BY x.price
HAVING SUM(SIGN(1-SIGN(y.price-x.price))) = (COUNT(*)+1)/2
AFAIU 你的问题。
@velcrow 的这个答案成功计算了中值。不幸的是,当有偶数行而不是计算 2 个中间行的平均值时,查询只会返回第二个值。我对查询进行了一些修改以满足您的需求:
--average value for middle rows
SELECT avg(t1.price) as median_val FROM (
SELECT @rownum:=@rownum+1 as `row_number`, d.price
FROM mediana d, (SELECT @rownum:=0) r
WHERE 1
-- put some where clause here
ORDER BY d.price
) as t1,
(
SELECT count(*) as total_rows
FROM mediana d
WHERE 1
-- put same where clause here
) as t2
WHERE 1
--this condition should return one record for odd number of rows and 2 middle records for even.
AND t1.row_number>=total_rows/2 and t1.row_number<=total_rows/2+1;