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我在 MYSQL 表名中有下表作为 a_ad_display 和列

╔═════════════╦═════════╦═════════╦═════════════════════╗
║ addisplayId ║ restId  ║ clicked ║     displaytime     ║
╠═════════════╬═════════╬═════════╬═════════════════════╣
║          1  ║  20707  ║      0  ║ 2013-02-28 10:50:55 ║
║          2  ║  20708  ║      1  ║ 2013-02-28 10:55:55 ║
║          3  ║  20711  ║      1  ║ 2013-03-01 12:50:55 ║
║          4  ║  20712  ║      1  ║ 2013-03-02 01:50:55 ║
║          5  ║  20707  ║      1  ║ 2013-03-03 10:50:55 ║
║          6  ║  20708  ║      1  ║ 2013-03-03 12:50:55 ║
║          7  ║  20707  ║      1  ║ 2013-03-04 09:50:55 ║
║          8  ║  20708  ║      1  ║ 2013-03-05 10:50:55 ║
║          9  ║  20708  ║      0  ║ 2013-03-06 11:50:55 ║
║         10  ║  20707  ║      0  ║ 2013-03-06 12:50:55 ║
╚═════════════╩═════════╩═════════╩═════════════════════╝

现在我想获取在 Clicked 列中具有最高并发 1 的 restId

所以从上面的记录中,20708 restId 具有最高的点击列数,即 3 ..所以我想在这种情况下获取 restId ..所以任何人都可以指导我如何做到这一点?

4

1 回答 1

1

这是最简单的答案,但它不会处理重复,

SELECT  restID, SUM(clicked) totalClick
FROM    a_ad_display
GROUP   BY restID
ORDER   BY totalClick DESC
LIMIT   1

这是将保留重复项的查询,

SELECT  restID, SUM(clicked) totalClick
FROM    a_ad_display
GROUP   BY restID
HAVING  SUM(clicked) = 
        (
            SELECT  SUM(clicked) totalClick
            FROM    a_ad_display
            GROUP   BY restID
            ORDER   BY totalClick DESC
            LIMIT   1
        )
于 2013-03-11T05:48:46.260 回答