如何使用 glm 从空间中的一个点创建广告牌平移矩阵?
问问题
2829 次
2 回答
5
mat4 billboard(vec3 position, vec3 cameraPos, vec3 cameraUp) {
vec3 look = normalize(cameraPos - position);
vec3 right = cross(cameraUp, look);
vec3 up2 = cross(look, right);
mat4 transform;
transform[0] = vec4(right, 0);
transform[1] = vec4(up2, 0);
transform[2] = vec4(look, 0);
// Uncomment this line to translate the position as well
// (without it, it's just a rotation)
//transform[3] = vec4(position, 0);
return transform;
}
于 2013-03-10T18:14:07.303 回答
3
只需将转换的左上角 3×3 子矩阵设置为身份。
更新:固定功能 OpenGL 变体:
void makebillboard_mat4x4(double *BM, double const * const MV)
{
for(size_t i = 0; i < 3; i++) {
for(size_t j = 0; j < 3; j++) {
BM[4*i + j] = i==j ? 1 : 0;
}
BM[4*i + 3] = MV[4*i + 3];
}
for(size_t i = 0; i < 4; i++) {
BM[12 + i] = MV[12 + i];
}
}
void mygltoolMakeMVBillboard(void)
{
GLenum active_matrix;
double MV[16];
glGetIntegerv(GL_MATRIX_MODE, &active_matrix);
glMatrixMode(GL_MODELVIEW);
glGetDoublev(GL_MODELVIEW_MATRIX, MV);
makebillboard_mat4x4(MV, MV);
glLoadMatrixd(MV);
glMatrixMode(active_matrix);
}
于 2013-03-10T18:14:56.307 回答