0

我有以下脚本,从底部向上几行我有一个window.location.href通过地址栏发布我的表单的结果。这很混乱,我想使用 POST 而不是 GET,有人有什么想法吗?

<script language="javascript">
function OnChangedUsername()
{
  if(document.signup.newuserid.value == "")
  {
    document.signup.btnCheckAvailability.disabled = true;
  }
  else
  {
    document.signup.btnCheckAvailability.disabled = false;
  }
}
function createRequestObject() {
  var ro;
  var browser = navigator.appName;
  if(browser == "Microsoft Internet Explorer"){
    ro = new ActiveXObject("Microsoft.XMLHTTP");
  }else{
    ro = new XMLHttpRequest();
  }
  return ro;
}

var http = createRequestObject();

function sndReq() {
  http.open('get', 'password_check.asp?emailaddress=<%Response.Write(emailaddress)%>&check=<%Response.Write(check)%>&password_check='+document.signup.newuserid.value);
  http.onreadystatechange = handleResponse;
  http.send(null);
}

function handleResponse() {
  if(http.readyState == 4){
    var response = http.responseText;
    var update = new Array();

    if(response.indexOf('|' != -1)) {
      update = response.split('|');
      document.getElementById("username_chk").innerHTML = update[0];


      if(document.getElementById("username_chk").innerHTML == "Ok") {
        window.location.href='detailsupdate.asp?username=<%Response.Write(sUsername)%>&check=<%Response.Write(check)%>&EmailAddress='+document.signup.EmailAddress.value+'&Address='+document.signup.Address.value+'&Address1='+document.signup.Address1.value+'&Address2='+document.signup.Address2.value+'&City='+document.signup.City.value+'&PostalCode='+document.signup.PostalCode.value+'&Country='+document.signup.Country.value+'&WorkPhone='+document.signup.WorkPhone.value+'&HomePhone='+document.signup.HomePhone.value+'&MobilePhone='+document.signup.MobilePhone.value+'&FaxNumber='+document.signup.FaxNumber.value+'&AlternativePhone='+document.signup.AlternativePhone.value+'&OO='+document.signup.OO.checked+'&Workshop='+document.signup.Workshop.checked+'&Raised='+document.signup.Raised.checked+'&Ground='+document.signup.Ground.checked+'&pd='+document.signup.newuserid.value+'&Tram='+document.signup.Tram.checked;
      }
    }
  }
}
</script>
4

2 回答 2

1

发出 POST 请求并将响应直接呈现到浏览器窗口的唯一方法是使用表单(您使用 DOM 生成)并提交它(您也可以通过 DOM 完成)。

另一种方法是使用 XMLHttpRequest(或其他一些 Ajax 技术)并使用 DOM 呈现响应。

于 2013-03-10T17:42:39.360 回答
1

无需将表单数据作为 GET 数据传递。您可以将方法指定为 POST。

<form action="script.asp" method="post">
   ...
   <input type="submit" value="submit">
</form>

您也不应该使用window.location.href. 这是非常丑陋的。当您提交表单时(单击提交按钮),它会将您的表单数据发布到 script.asp。

另一种提交表单的方法是通过 DOM 提交。document.forms[0].submit();

于 2013-03-10T17:43:22.687 回答