该页面http://daeken.pastebin.ca/raw/843310包含所有汇编代码及其描述。但我不是很明白，例如0xa1 : ['MOV', 'rAX,Ov'],...，看它的描述我无法弄清楚它是什么意思。
这里有很多这样的例子：
Ob - Ov - rAX - Yb - Xb - etc...
谁能解释一下那些奇怪的符号是什么意思？
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例如：
0xa1 : ['MOV', 'rAX,Ov']
根据英特尔® 64 和 IA-32 架构开发人员手册：组合卷表 A-2。一字节操作码映射：(00H — F7H)0xa1是mov rAX, Ov.
然后表 A.2.1 寻址方法代码解释了寻址中使用的缩写：
O The instruction has no ModR/M byte. The offset of the operand is coded as
a word or double word (depending on address size attribute) in the instruction.
No base register, index register, or scaling factor can be applied (for example,
MOV (A0–A3)).
表 A.2.2 操作数类型代码解释了操作数类型：
v Word, doubleword or quadword (in 64-bit mode), depending on operand-size
attribute.
And below A.2.3 Register Codes it says:
A register identifier of the form eXX or rXX is used when register width depends
on the operand-size attribute. eXX is used when 16 or 32-bit sizes are possible;
rXX is used when 16, 32, or 64-bit sizes are possible. For example: eAX indicates
that the AX register is used when the operand-size attribute is 16 and the EAX
register is used when the operand-size attribute is 32. rAX can indicate AX, EAX
or RAX.
So here are some example instruction encodings for 0xa1 opcode (confirmed with udcli -x):
a10102 mov ax, [0x201] ; in x86 16-bit code
a101020304 mov eax, [0x4030201] ; in x86 32-bit code
a10102030405060708 mov eax, [0x807060504030201] ; in x86-64
66a101020304 mov ax, [0x4030201] ; with 0x66, in x86 32-bit code
66a10102030405060708 mov ax, [0x807060504030201] ; with 0x66, in x86-64
48a10102030405060708 mov rax, [0x807060504030201] ; with 0x48 REX.W, in x86-64
于 2013-03-10T10:36:44.080 回答
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于 2013-03-10T10:36:06.110 回答