我必须承认,关于 PHP 的“引用传递”的所有困惑都影响了我,现在我还不清楚。我会想到以下代码:
class TestClass {
private $my_precious = array ('one','two','three');
public function &give_reference() {
return $this->my_precious;
}
}
$foobar = new TestClass();
$my_ref = $foobar->give_reference();
$my_ref = array ("four", "five", "six");
echo print_r($foobar,true);
会打印:
TestClass Object
(
[my_precious:TestClass:private] => Array
(
[0] => four
[1] => five
[2] => six
)
)
但是,唉,我的参考似乎没有持久力,而只是回声:
TestClass Object
(
[my_precious:TestClass:private] => Array
(
[0] => one
[1] => two
[2] => three
)
)
我怎样才能使这项工作?