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我有一些代码来绘制矩形。它用于在 a 上绘制矩形JPanel，以标记小部件的边界。这里首先是代码，然后我将解释我的问题cq。问题。

首先，我有一个WidgetDrawingPanel扩展类 ( ) JPanel。

public WidgetDrawingPanel(int width, int height) {
    /*To make things visible at least*/
    widgets.add(new Widget(10,10,100,100, WidgetType.TextField));
    widgets.add(new Widget(50,50,100,200, WidgetType.TextField));
    this.width = width;
    this.height = height;
    this.setBackground(Color.BLUE);
    addListener(); //adds both MouseMotionListener and MouseListener
}

下面你会看到我参考ch了很多。这是一个CoordinateHolder，它保存了我的鼠标移动的开始坐标和当前坐标。

private void addListener() {
    this.addMouseMotionListener(new MouseMotionListener() {
        @Override
        public void mouseDragged(MouseEvent arg0) {
            ch.currentX = arg0.getX();
            ch.currentY = arg0.getY();
            System.out.println("dragging " + ch.currentX + ","+ch.currentY);
            WidgetDrawingPanel.this.repaint();
        }
    });
    this.addMouseListener(new MouseListener() {
        @Override
        public void mouseReleased(MouseEvent event) {
            ch.endX = event.getX();
            ch.endY = event.getY();
            try {
                checkCoords();
            } catch (OutsidePanelException e) {
                e.printStackTrace();
                JOptionPane.showMessageDialog(null, "drawn Outside Panel");
            }
        }

        @Override
        public void mousePressed(MouseEvent event) {
            ch = new CoordinateHolder(event.getX(), event.getY());
        }
    });
}

最后是paintComponent(Grapics)方法。有循环Widgets，实际上只是已经绘制Rects（x，y，w，h 属性），但其中包含更多信息，这在应用程序的绘图部分中没有用。每次释放鼠标时，CoordinateHolder都会转换为 Widget，并添加到widgets.

@Override
public void paintComponent(Graphics g) {
    super.paintComponent(g);
    System.out.println("Paint");
    g.setColor(Color.BLUE);
    g.fillRect(0, 0, width, height); //making the whole panel blue
    g.setColor(Color.RED);
    Graphics2D g2 = (Graphics2D)g;
    g2.setStroke(new BasicStroke(3));
    for (Widget w : widgets) { 
        g.drawRect(w.getX(), w.getY(), w.getW(), w.getH());
    }
    if (ch != null)
        g.drawRect(ch.startX, ch.startY, ch.currentX - ch.startX, ch.currentY - ch.startY);
}

这段代码正在运行，但我怀疑这是非常低效和低效的，因为上面的代码会不断刷新JPanel鼠标拖动，也就是说，每 10 毫秒一次？我想它很快就会变慢，尤其是当用户创建大量矩形时（它们也会不断地重绘，如 参考资料所示painComponent(Graphics)）。

问题cq。问题

有没有更好、资源消耗更少的方法，用户可以平滑地拖动矩形？

我在 Java 中阅读了对 JFrame 上的 Drag rectangle的答案，但该答案的作者似乎和我一样。但是再一次，这太低效了，对吧？或者计算机是否应该能够轻松地不断重绘组件，这实际上是一种有效的方法吗？

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1 回答 1

4

要显示许多不变的背景形状，请将它们绘制到 BufferedImage，然后在paintComponent(...)方法中显示该 BufferedImage。因此，在绘制形状时，将其绘制进去，paintComponent(...)但一旦绘制完成，可能在 mouseRelease 上，然后在后台 BufferedImage 中绘制它。

请注意，最会减慢您当前绘图代码的可能是您的调试 SOP 语句，但我假设这些将从完成的代码中删除。

例如：

import java.awt.*;
import java.awt.event.*;
import java.awt.image.BufferedImage;

import javax.swing.*;

@SuppressWarnings("serial")
public class DrawingPanel extends JPanel {
   private static final int PREF_W = 600;
   private static final int PREF_H = 400;
   private static final Color DRAWING_COLOR = new Color(255, 100, 200);
   private static final Color FINAL_DRAWING_COLOR = Color.red;

   private BufferedImage backgroundImg;
   private Point startPt = null;
   private Point endPt = null;
   private Point currentPt = null;

   public DrawingPanel() {
      backgroundImg = new BufferedImage(PREF_W, PREF_H,
            BufferedImage.TYPE_INT_ARGB);
      Graphics g = backgroundImg.getGraphics();
      g.setColor(Color.blue);
      g.fillRect(0, 0, PREF_W, PREF_H);
      g.dispose();

      MyMouseAdapter myMouseAdapter = new MyMouseAdapter();
      addMouseMotionListener(myMouseAdapter);
      addMouseListener(myMouseAdapter);
   }

   @Override
   protected void paintComponent(Graphics g) {
      super.paintComponent(g);
      if (backgroundImg != null) {
         g.drawImage(backgroundImg, 0, 0, this);
      }

      if (startPt != null && currentPt != null) {
         g.setColor(DRAWING_COLOR);
         int x = Math.min(startPt.x, currentPt.x);
         int y = Math.min(startPt.y, currentPt.y);
         int width = Math.abs(startPt.x - currentPt.x);
         int height = Math.abs(startPt.y - currentPt.y);
         g.drawRect(x, y, width, height);
      }
   }

   @Override
   public Dimension getPreferredSize() {
      return new Dimension(PREF_W, PREF_H);
   }

   public void drawToBackground() {
      Graphics g = backgroundImg.getGraphics();
      g.setColor(FINAL_DRAWING_COLOR);
      int x = Math.min(startPt.x, endPt.x);
      int y = Math.min(startPt.y, endPt.y);
      int width = Math.abs(startPt.x - endPt.x);
      int height = Math.abs(startPt.y - endPt.y);
      g.drawRect(x, y, width, height);
      g.dispose();

      startPt = null;
      repaint();
   }

   private class MyMouseAdapter extends MouseAdapter {
      @Override
      public void mouseDragged(MouseEvent mEvt) {
         currentPt = mEvt.getPoint();
         DrawingPanel.this.repaint();
      }

      @Override
      public void mouseReleased(MouseEvent mEvt) {
         endPt = mEvt.getPoint();
         currentPt = null;
         drawToBackground();
      }

      @Override
      public void mousePressed(MouseEvent mEvt) {
         startPt = mEvt.getPoint();
      }
   }

   private static void createAndShowGui() {
      DrawingPanel mainPanel = new DrawingPanel();

      JFrame frame = new JFrame("Drawing Panel");
      frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
      frame.getContentPane().add(mainPanel);
      frame.pack();
      frame.setLocationByPlatform(true);
      frame.setVisible(true);
   }

   public static void main(String[] args) {
      SwingUtilities.invokeLater(new Runnable() {
         public void run() {
            createAndShowGui();
         }
      });
   }
}
于 2013-03-09T15:08:54.253 回答