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我正在使用以下代码将照片发送到 Web 服务：

-(void)uploadPhoto:(UIImage*)image :(NSString*)fileName
{

NSData *img = UIImageJPEGRepresentation(image, 0.9f);

NSString *urlString = @"http://serverURL.com";

NSMutableURLRequest *request= [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];

NSString *boundary = @"---------------------------14737809831466499882746641449";

NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
[request addValue:contentType forHTTPHeaderField: @"Content-Type"];

NSMutableData *postbody = [NSMutableData data];

[postbody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

[postbody appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"userfile\"; filename=\"%@.jpg\"\r\n",fileName] dataUsingEncoding:NSUTF8StringEncoding]];

[postbody appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]];

[postbody appendData:[NSData dataWithData:img]];
[postbody appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

[request setHTTPBody:postbody];

NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
NSLog(@"%@", returnString);

}

这工作正常，我可以从 PHP 中的服务器获取照片。

我的问题是，是否可以使用表单数据向服务器发送其他数据？我需要发送有关照片的更多详细信息，例如用户名和其他一些与应用程序相关的数据。

我想知道如何在请求中附加一些额外的数据。我试图将常规的 POST 数据附加到它，但它不起作用。我假设是因为数据类型。

我很困惑这是如何工作的，以及是否有办法将更多数据附加到我发送到服务器的请求中。

对此的任何帮助都会很棒。

谢谢！

4

2 回答 2

1

To upload image on server one of the best way is to use ASIFormDataRequest.

You can send multiple values for the same parameter using the alternative add API:

ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request addPostValue:@"Ben" forKey:@"names"];
[request addPostValue:@"George" forKey:@"names"];
[request addFile:@"/Users/ben/Desktop/ben.jpg" forKey:@"photos"];
[request addData:imageData withFileName:@"george.jpg" andContentType:@"image/jpeg" forKey:@"photos"];

For a working code Uploading file to server using ASIFormDataRequest. Some part of how to use it...

ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];

[request setUseKeychainPersistence:YES];
//if you have your site secured by .htaccess

//[request setUsername:@"login"];
//[request setPassword:@"password"];

NSString *fileName = [NSString stringWithFormat:@"ipodfile%@.jpg",self.fileID];
[request addPostValue:fileName forKey:@"name"];

To have better idea for Sending a form POST with ASIFormDataRequest.

于 2013-03-08T19:54:41.360 回答
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只需为帖子中的每个变量重复以下几行：

[postbody appendData:[@"Content-Disposition: form-data; name=\"userfile\"\r\n" dataUsingEncoding:NSUTF8StringEncoding]];

[postbody appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]];

[postbody appendData:[NSData dataWithData:img]];
[postbody appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

显然，您需要更新第一行中的name值、第二行中的内容类型以及第三行中的实际数据。

于 2013-03-08T19:59:16.750 回答