4

我有以下课程:

public class UserObject implements Serializable
{
    public Integer id;
    public String name;
    public String phoneno;

    public UserObject()
    {
        this.id = new Integer(0);
        this.name = "";
        this.phoneno = "";
   }
}

我有一个json如下字符串:

[
    {
        "id": 1,
        "name": "First Name",
        "phoneno": "0123452",
    },
    {
        "id": 2,
        "name": "Second Name",
        "phoneno": "0123452",
    },
    {
        "id": 3,
        "name": "Third Name",
        "phoneno": "0123455",
   }
]

我可以使用以下代码轻松地从CollectionofUserObject转换为:JSON

Collection users = new Vector();
UserObject userObj = new UserObject();

userObj.id=1; userObj.name="First Name"; userObj.phoneno="0123451";
users.add(userObj);
userObj.id=2; userObj.name="Second Name"; userObj.phoneno="0123452";
users.add(userObj);
userObj.id=3; userObj.name="Second Name"; userObj.phoneno="0123455";
users.add(userObj);

Gson gson = new Gson();
String json = gson.toJson(users);

但我不知道如何转换JSON stringcollectionof objects?我发现我可以使用gson.fromJson()但不知道如何使用 for Collection。请帮忙。

4

2 回答 2

6

Collection以下代码允许您获取UserObject

Type token = new TypeToken<Collection<UserObject>>() {}.getType();
Collection<UserObject> result = gson.fromJson(json, token);

另外,请注意json问题中提供的内容无效,因为phoneno字段后有一个额外的逗号。这是正确的:

[
    {
        "id": 1,
        "name": "First Name",
        "phoneno": "0123452"
    },
    {
        "id": 2,
        "name": "Second Name",
        "phoneno": "0123452"
    },
    {
        "id": 3,
        "name": "Third Name",
        "phoneno": "0123455"
    }
]
于 2013-03-08T18:03:40.610 回答
3

鉴于此 JSON,您的包装类应如下所示:

public class Data {
    private List<User> users;
    // +getters/setters
}

public class User {
    private String name;
    private String email;
    private List<User> friends;
    // +getters/setters
}

然后转换它,使用

Data data = gson.fromJson(this.json, Data.class);

并获得用户,使用

List<User> users = data.getUsers();
于 2013-03-08T17:52:38.287 回答