鉴于:
grammar Hbs;
var: START_DELIM ID END_DELIM;
START_DELIM: '{{';
END_DELIM: '}}';
我想知道如何在运行时更改为例如START_DELIM
和.END_DELIM
<%
%>
有谁知道如何在 ANTLR 4 中做到这一点?
谢谢。
鉴于:
grammar Hbs;
var: START_DELIM ID END_DELIM;
START_DELIM: '{{';
END_DELIM: '}}';
我想知道如何在运行时更改为例如START_DELIM
和.END_DELIM
<%
%>
有谁知道如何在 ANTLR 4 中做到这一点?
谢谢。
有一种方法,但您需要将您的语法与目标语言联系起来(到目前为止,唯一的目标是 Java)。
这是一个快速演示(我包括一些评论来澄清事情):
grammar T;
@lexer::members {
// Some default values
private String start = "<<";
private String end = ">>";
public TLexer(CharStream input, String start, String end) {
this(input);
this.start = start;
this.end = end;
}
boolean tryToken(String text) {
// See if `text` is ahead in the CharStream.
for(int i = 0; i < text.length(); i++) {
if(_input.LA(i + 1) != text.charAt(i)) {
// Nope, we didn't find `text`.
return false;
}
}
// Since we found the text, increase the CharStream's index.
_input.seek(_input.index() + text.length() - 1);
return true;
}
}
parse
: START ID END
;
START
: {tryToken(start)}? .
// The `.` is needed because a lexer rule must match at least 1 char.
;
END
: {tryToken(end)}? .
;
ID
: [a-zA-Z]+
;
SPACE
: [ \t\r\n] -> skip
;
是{ ... }?
语义谓词。见:https ://github.com/antlr/antlr4/blob/master/doc/predicates.md
这是一个小测试类:
import org.antlr.v4.runtime.*;
import org.antlr.v4.runtime.tree.*;
public class Main {
private static void test(TLexer lexer) throws Exception {
TParser parser = new TParser(new CommonTokenStream(lexer));
ParseTree tree = parser.parse();
System.out.println(tree.toStringTree(parser));
}
public static void main(String[] args) throws Exception {
// Test with the default START and END.
test(new TLexer(new ANTLRInputStream("<< foo >>")));
// Test with a custom START and END.
test(new TLexer(new ANTLRInputStream("<? foo ?>"), "<?", "?>"));
}
}
运行演示如下:
java -jar antlr-4.0-complete.jar T.g4
javac -cp .:antlr-4.0-complete.jar *.java
java -cp .:antlr-4.0-complete.jar Main
java -jar antlr-4.0-complete.jar T.g4
javac -cp .;antlr-4.0-complete.jar *.java
java -cp .;antlr-4.0-complete.jar Main
您会看到以下内容被打印到控制台:
(parse << foo >>)
(parse <? foo ?>)