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使用类型生成器我可以动态创建类型。是否可以从匿名类型执行此操作?

到目前为止我有这个;

//CreateType generates a type (so that I can set it's properties once instantiated) from an //anonymous object. I am not interested in the initial value of the properties, just the Type.
 Type t = CreateType(new {Name = "Ben", Age = 23});
 var myObject = Activator.CreateInstance(t);

现在可以使用类型“t”作为类型参数吗?

我的方法:

public static void DoSomething<T>() where T : new() 
{
}

我想使用动态创建的类型“t”来调用这个方法。这样我就可以打电话;

DoSomething<t>(); //This won't work obviously
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1 回答 1

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对的,这是可能的。要将类型用作类型参数,您需要使用MakeGenericType方法:

// Of course you'll use CreateType here but this is what compiles for me :)
var anonymous = new { Value = "blah", Number = 1 };
Type anonType = anonymous.GetType();

// Get generic list type
Type listType = typeof(List<>);
Type[] typeParams = new Type[] { anonType };
Type anonListType = listType.MakeGenericType(typeParams);

// Create the list
IList anonList = (IList)Activator.CreateInstance(anonListType);

// create an instance of the anonymous type and add it
var t = Activator.CreateInstance(anonType, "meh", 2); // arguments depending on the constructor, the default anonymous type constructor just takes all properties in their declaration order
anonList.Add(t);
于 2013-03-08T11:15:57.363 回答