datetime - Powershell - 将军事时间字符串转换为日期时间

Question

我正在寻找一种将军事时间字符串（“22:12:02”）转换为日期时间对象的方法。

下面是代码示例：

$TimePrevious = $Null
[array]$TimeArray = "22:12:02.000", "22:12:03.000", "23:12:02.000"

$TimeArray | ForEach-Object {
    $TimeCurrent = $_.Substring(0,8)
    $TimeDifference = [datetime]$TimeCurrent.TimeOfDay - [datetime]$TimePrevious.TimeOfDay
    If ($TimeDifference.Second -lt "10") {Write-Host "$_ is less than 10 seconds"}
    $TimePrevious = $_
    }

错误显示“无法将“System.TimeSpan”类型的“22:12:02”值转换为“System.DateTime”类型

Answer 1

默认解析器似乎可以使用：

[datetime]"22:12:02"

2013 年 3 月 7 日星期四晚上 10:12:02

Answer 2

对不起。我刚刚开始工作：

$TimePrevious = $Null
[array]$TimeArray = "22:12:02.000", "22:12:03.000", "23:12:02.000"

$TimeArray | ForEach-Object {
    $TimeCurrent = $_.Substring(0,8)
    $TimeDifference = [datetime]$TimeCurrent - [datetime]$TimePrevious
    If ($TimeDifference.TotalSeconds -lt "10") {Write-Host "$_ is less than 10 seconds"}
    $TimePrevious = $_
    }

感谢您的快速回复。