@JaredPar 是正确的,没有内在的方法来做切片 - 也就是说,你可以设计一个扩展方法来做到这一点:
public static class Ext
{
public static T[] Slice<T>(this T[] source, int fromIdx, int toIdx)
{
T[] ret = new T[toIdx - fromIdx + 1];
for(int srcIdx=fromIdx, dstIdx = 0; srcIdx <= toIdx; srcIdx++)
{
ret[dstIdx++] = source[srcIdx];
}
return ret;
}
public static T[,] Slice<T>(this T[,] source, int fromIdxRank0, int toIdxRank0, int fromIdxRank1, int toIdxRank1)
{
T[,] ret = new T[toIdxRank0 - fromIdxRank0 + 1, toIdxRank1 - fromIdxRank1 + 1];
for(int srcIdxRank0=fromIdxRank0, dstIdxRank0 = 0; srcIdxRank0 <= toIdxRank0; srcIdxRank0++, dstIdxRank0++)
{
for(int srcIdxRank1=fromIdxRank1, dstIdxRank1 = 0; srcIdxRank1 <= toIdxRank1; srcIdxRank1++, dstIdxRank1++)
{
ret[dstIdxRank0, dstIdxRank1] = source[srcIdxRank0, srcIdxRank1];
}
}
return ret;
}
}
和一个测试:
void Main()
{
var singleArr = new int[]{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
singleArr.Slice(2, 4).Dump();
var doubleArr = new int[,]
{
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
};
doubleArr.Slice(2, 4, 2, 4).Dump();
}