出于某种原因,我无法弄清楚如何在以下脚本中停止双重动画:
<script type="text/javascript">
$(document).ready(function() {
var activeNews = "01";
$(".newsNav.forward").click(function(event) {
event.preventDefault();
if (activeNews == 01) {
$(".newsItem.01").stop(true, true).fadeOut(250, function() {
$(".newsItem.02").stop(true, true).fadeIn(250);
});
activeNews = 02;
} else if (activeNews == 02) {
$(".newsItem.02").stop(true, true).fadeOut(250, function() {
$(".newsItem.03").stop(true, true).fadeIn(250);
});
activeNews = 03;
} else if (activeNews == 03) {
$(".newsItem.03").stop(true, true).fadeOut(250, function() {
$(".newsItem.01").stop(true, true).fadeIn(250);
});
activeNews = 01;
}
});
});
</script>
当您单击.newsNav.forward
太快时,.newsItems
会出现多个,而不仅仅是一个。如您所见,我知道.stop();
应该可以解决此问题,但我不知道为什么它不起作用。
HTML(如果相关):
<div id="news">
<a class="newsNav back" href="#"><</a>
<a class="newsNav forward" href="#">></a>
<h1>Latest News</h1>
<div id="newsSlider">
<p class="newsItem 01 active">First News Item</p>
<p class="newsItem 02">Second News Item</p>
<p class="newsItem 03">Third News Item</p>
</div><!--/#newsSlider-->
<div style="clear:both;"></div>
</div><!--/#news-->
相关的CSS也是:
#contentWrapper #content #news #newsSlider p.newsItem {
display: none;
}
#contentWrapper #content #news #newsSlider p.newsItem.active {
display: block;
}