4

我现在有来自服务器的 JSON 响应,但我想根据日期对其进行重组。例如,我现在有

{
"items":
    [
        {
            "A": [
                {
                    "name": "a",
                    "date": "2/10/2010",
                    "sales": "100"
                },
                {
                    "name": "b",
                    "date": "6/10/2010",
                    "sales": "400"
                }
            ],
            "B": [
                {
                    "name": "c",
                    "date": "2/10/2010",
                    "sales": "1000"
                },
                {
                    "name": "d",
                    "date": "6/10/2010",
                    "sales": "400"
                }
            ]
        },
        {
            "C": [
                {
                    "name": "a",
                    "date": "10/10/2010",
                    "sales": "100"
                },
                {
                    "name": "b",
                    "date": "6/10/2010",
                    "sales": "100"
                }
            ],
            "D": [
                {
                    "name": "c",
                    "date": "2/10/2010",
                    "sales": "300"
                },
                {
                    "name": "c",
                    "date": "2/10/2010",
                    "sales": "1100"
                }
            ]
        }
    ]
}

但现在我想按日期重组,对于特定的一天需要知道所有的销售情况,

    {
    "date1" : [sales, sales, sales],
    "date2" : [sales, sales],
    "date3" : [sales]
    }

如何才能做到这一点?

4

2 回答 2

4

我只能假设你想要这个:

var arr = JSON.parse(response); // or something like that (assuming valid JSON)
                                // or just assign the array literal

var result = {};
for (var i=0; i<arr.length; i++) {
    var date = arr[i].date,
        sales = arr[i].sales;
    if (date in result)
        result[date].push(sales);
    else
        result[date] = [sales];
}
于 2013-03-07T19:15:32.493 回答
0

假设你得到了你的 JSON:

<?php
$list = array(
    array(
        'product'   => 'a',
        'date'      => '2012-08-01',
        'sales'     => 500,
    ),
    array(
        'product'   => 'b',
        'date'      => '2012-08-02',
        'sales'     => 600,
    ),
    array(
        'product'   => 'c',
        'date'      => '2012-08-01',
        'sales'     => 250,
    ),
    array(
        'product'   => 'd',
        'date'      => '2012-08-02',
        'sales'     => 800,
    ),
);

echo json_encode($list);
?>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
var JSON = '<?php echo json_encode($list); ?>';
var pJson = jQuery.parseJSON(JSON);

var cArray = new Array();

for each ( i in pJson ) {
         if ( typeof cArray[i.date] == 'undefined' ) {
                cArray[i.date] = Array();
         }
        cArray[i.date].push(i.sales);
}
</script>

我添加了 php 部分以显示 JSON 字符串的外观。此解决方案还需要 jQuery。

于 2013-03-07T19:42:45.870 回答