sql - 用于查找第二高的 SQL

Question

假设我有一张员工表，我在其中一列中维护员工的姓名，在另一列中维护他们提取的薪水。我应该写什么 SQL 来找到获得第二高薪水的员工的名字？？？

Answer 1

我会使用row_number()：

select e.*
from (select e.*, row_number() over (order by salary desc) as seqnum
      from employees e
     ) e
where seqnum = 1

其他人提到了limit//方法top：rownum

select e.*
from (select e.*
      from employees e
      order by salary desc
      limit 2
     ) t
order by salary
limit 1

你可以用偏移量做同样的事情：

select e.*
from employees e
order by salary desc
limit 2, 1

但是，如果您与最高薪水并列，那么所有这些都有问题。第一种方法很容易通过替换row_number()为dense_rank()：

select e.*
from (select e.*, dense_rank() over (order by salary desc) as seqnum
      from employees e
     ) e
where seqnum = 1

而且，另一种方法是：

select e.*
from employees e
where e.salary < (select max(salary) from employees)
order by salary desc
limit 1  -- or top 1 or rownum = 1 etc.

Answer 2

您可以尝试从“Top 2”中选择，按升序排序，然后是“Top 1”，它应该为您提供正确的行。

Answer 3

您可以执行以下操作：

select * from (select * from Employees order by salary desc limit 2) as A order by salary asc limit 1;