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如何在此代码(导出到 xls)中写不是字段名称而是字段的详细名称(在列标题中)?

def export_as_xls(modeladmin, request, queryset):
    if not request.user.is_staff:
        raise PermissionDenied
    opts = modeladmin.model._meta

    wb = Workbook()
    ws0 = wb.add_sheet('0')
    col = 0
    field_names = []
    # write header row
    for field in opts.fields:
        ws0.write(0, col, field.name)
        field_names.append(field.name)
        col = col + 1

    row = 1
    # Write data rows
    for obj in queryset:
        col = 0
        for field in field_names:
            val = unicode(getattr(obj, field)).strip()
            ws0.write(row, col, val)
            col = col + 1
        row = row + 1   

    f = StringIO()
    wb.save(f)
    f.seek(0)
    response = HttpResponse(f.read(), mimetype='application/ms-excel')
    response['Content-Disposition'] = 'attachment; filename=%s.xls' % unicode(opts).replace('.', '_')
    return response

export_as_xls.short_description = "Export selected objects to XLS"

我看到field.name了,但我不知道如何改变它。此代码来自 django 片段站点

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1 回答 1

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我可能会误解这个问题,但如果你想更改 field.name:

for field in opts.fields:
    field.name = 'Foo'

这会将所有字段名称更改为“Foo”

于 2013-03-07T18:59:19.037 回答