我正在使用最新的 java Eclipse 软件,当我运行这个 HttpPost 代码时模拟器崩溃了。我在笔记本电脑上安装了 uniserver,所以我将它用作服务器。
此代码应该调用上一个类中的编辑文本数据,并使用 HttpPost 请求将此数据发布到在线表单上各自的字段中。
编辑文本数据是 3 个字段:“From”、“To”和“Message”。而且我在服务器上创建的表单也有这些相同的字段来输入数据。(“ http://19x.xx.xx.xxx/androidp2p/testform.php ”)其中 19x.xx.xx.xxx 是我的(本地主机)IP 地址。
我从上一个课程中正确提取了该数据,并且我的代码类似于我在网上找到的 HttpPost 示例,但我不确定它为什么会崩溃。
我附上了我试图查看是否可以获得任何帮助的 HttpPost 方法。提前谢谢你。
方法一:
String myBreadu, myBreadr, myBreadm;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
Bundle myBasket = getIntent().getExtras();
myBreadu = myBasket.getString("keyfrom");
myBreadr = myBasket.getString("keyto");
myBreadm = myBasket.getString("keymsg");
// Create a new HttpClient and Post Header
HttpClient client = new DefaultHttpClient();
String postURL = ("http://19x.xx.xx.xxx/androidp2p/testform.php");
HttpPost post = new HttpPost(postURL);
try {
// Add the data
List<NameValuePair> pairs = new ArrayList<NameValuePair>(3);
pairs.add(new BasicNameValuePair("keysendu", myBreadu));
pairs.add(new BasicNameValuePair("keysendr", myBreadr));
pairs.add(new BasicNameValuePair("keysendm", myBreadm));
UrlEncodedFormEntity uefe = new UrlEncodedFormEntity(pairs);
post.setEntity(uefe);
// Execute the HTTP Post Request
HttpResponse response = client.execute(post);
// Convert the response into a String
HttpEntity resEntity = response.getEntity();
if (resEntity != null) {
Log.i("RESPONSE", EntityUtils.toString(resEntity));
}
} catch (UnsupportedEncodingException uee) {
uee.printStackTrace();
} catch (ClientProtocolException cpe) {
cpe.printStackTrace();
} catch (IOException ioe) {
ioe.printStackTrace();
}
}
方法二:
String myBreadu, myBreadr, myBreadm;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
Bundle myBasket = getIntent().getExtras();
myBreadu = myBasket.getString("keyfrom");
myBreadr = myBasket.getString("keyto");
myBreadm = myBasket.getString("keymsg");
String result = null;
// Create a new HttpClient and Post Header
HttpClient client = new DefaultHttpClient();
String postURL = ("http://186.45.107.129/androidp2p/testform.php");
HttpPost post = new HttpPost(postURL);
try {
// Add the data
List<NameValuePair> pairs = new ArrayList<NameValuePair>(3);
pairs.add(new BasicNameValuePair("keysendu", myBreadu));
pairs.add(new BasicNameValuePair("keysendr", myBreadr));
pairs.add(new BasicNameValuePair("keysendm", myBreadm));
UrlEncodedFormEntity uefe = new UrlEncodedFormEntity(pairs);
post.setEntity(uefe);
// Execute the HTTP Post Request
HttpResponse response = client.execute(post);
// Convert the response into a String
HttpEntity resEntity = response.getEntity();
BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String l = "";
StringBuilder sb = new StringBuilder();
while ((l = rd.readLine()) != null) {
sb.append(l + "\n");
}
rd.close();
String result = sb.toString(); // this line gives an error "Duplicate local variable result"
} catch (UnsupportedEncodingException uee) {
uee.printStackTrace();
} catch (ClientProtocolException cpe) {
cpe.printStackTrace();
} catch (IOException ioe) {
ioe.printStackTrace();
}
}
这是testform.PHP
测试表
从:到:
消息:
请问我可以再添加一件事吗?我不确定是否应该将数据直接发送到表单或我拥有的其他 PHP 页面。
顺便说一下,当我尝试 HttpPost 时,我在日志中遇到的错误是:
FATAL EXCEPTION: main
03-07 11:36:23.226: E/AndroidRuntime(1490): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.project.keegan/com.project.keegan.SendPostMethod}: android.os.NetworkOnMainThreadException
03-07 11:36:23.226: E/AndroidRuntime(1490): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2059)
03-07 11:36:23.226: E/AndroidRuntime(1490): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2084)
03-07 11:36:23.226: E/AndroidRuntime(1490): at android.app.ActivityThread.access$600(ActivityThread.java:130)
对不起,如果这是太多的信息,伙计们。谢谢。