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我已经数过铭文,这周。但我需要在过去 12 周内每周计算题字,并将其以数组形式发送。

我的实际要求是:

SELECT COUNT(*) FROM PERSON
YEAR(date_inscription) = YEAR(NOW())
AND WEEK(date_inscription) = WEEK(NOW())
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1 回答 1

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SELECT YEARWEEK(date_inscription) as yweek,
       COUNT(*) as cnt
FROM PERSON
where YEARWEEK(date_inscription) >= YEARWEEK(curdate()) - 12
group by yweek
于 2013-03-07T14:18:53.013 回答