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我也在尝试实施这个项目，但我收到了 ^Title^ 错误。

我知道这个错误已被重新发布。请参见此处：错误：构造函数 MainActivity.ScreenSlidePagerAdapter(FragmentManager) 未定义，此处： 尽管我有 android-support-v13 库，但 Eclipse 无法识别 android.support.v13.app.FragmentActivity

但没有一个答案解决了我的问题。也许图书馆有问题还是？

这是我的代码。

package kn.screenslide;

import android.app.Fragment;
import android.app.FragmentManager;
import android.content.Intent;
import android.os.Bundle;
import android.support.v4.app.FragmentStatePagerAdapter;
import android.support.v4.app.FragmentActivity;
import android.support.v4.app.NavUtils;
import android.support.v4.view.PagerAdapter;
import android.support.v4.view.ViewPager;
import android.view.Menu;
import android.view.MenuItem;

public class ScreenSlideActivity extends FragmentActivity {
     //The number of pages (wizard steps) to show in this demo.
    private static final int NUM_PAGES = 5;

//The pager widget, which handles animation and allows swiping horizontally to access previous and next wizard steps.

    private ViewPager mPager;

     //The pager adapter, which provides the pages to the view pager widget.
    private PagerAdapter mPagerAdapter;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_screen_slide);

        // Instantiate a ViewPager and a PagerAdapter.
        mPager = (ViewPager) findViewById(R.id.pager);
        mPagerAdapter = new ScreenSlidePagerAdapter(getSupportFragmentManager());
        mPager.setAdapter(mPagerAdapter);
        mPager.setOnPageChangeListener(new ViewPager.SimpleOnPageChangeListener() {
            @Override
            public void onPageSelected(int position) {
                // When changing pages, reset the action bar actions since they are dependent
                // on which page is currently active. An alternative approach is to have each
                // fragment expose actions itself (rather than the activity exposing actions),
                // but for simplicity, the activity provides the actions in this sample.
                invalidateOptionsMenu();
            }
        });
    }

        //A simple pager adapter that represents 5 {@link ScreenSlidePageFragment} objects, in sequence.

    private class ScreenSlidePagerAdapter extends FragmentStatePagerAdapter {
        public ScreenSlidePagerAdapter(android.support.v4.app.FragmentManager fm) {
            super(fm);
        }


        //This is where fragments are created
        @Override
        public android.support.v4.app.Fragment getItem(int position) {
            return ScreenSlidePageAdapter.create(position);
        }

        @Override
        public int getCount() {
            return NUM_PAGES;
        }
    }
}
4

1 回答 1

1

问题在ScreenSlidePageAdapter.getItem(). 适配器没有 create() 方法。

//This is where fragments are created
@Override
public android.support.v4.app.Fragment getItem(int position) {
    return ScreenSlidePageAdapter.create(position);
}

您必须在此处返回 Fragment，而不是适配器。

于 2013-03-21T16:27:11.577 回答