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我正在使用 C# WPF MVVM。所以在 XAML 中有一个列表视图，它绑定到一个对象，用于根据选项卡显示来自 sql 数据库的不同信息。

例如。我有两种形式：一种是显示信息，另一种是用于输入信息。在另一种形式中输入新信息后，如何自动更新一种形式的列表视图？因为现在我必须切换标签才能更新列表视图。

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2 回答 2

1

After you enter new information into a form, try to invoke your own method, which will update your information into a list view. So you can use some event eg. DataContentChanged or your update method can be called when u click the button which adds new data into your form. Example of refresh method should look like this:

public void lbRefresh()        
{
    //create itemsList for listbox
    ArrayList itemsList = new ArrayList();
    //count how many information you wana to add
    //here I count how many columns I have in dataGrid1
    int count = dataGrid1.Columns.Count;
    //for cycle to add my strings of columns headers into an itemsList
    for (int i = 0; i < count; i++)
    {
        itemsList.Add(dataGrid1.Columns[i].Header.ToString());
    }
    //simply refresh my itemsList into my listBox1
    listBox1.ItemsSource = itemsList;
}

EDIT: To finish and solve your problem, try to use this snippet of code: 

//some btn_Click Event in one window 
//(lets say, its your callback " to update" button in datagrid)
private void Button_Click_1(object sender, RoutedEventArgs e)
{
    //here you doing somethin
    //after your datagrid got updated, try to store the object, 
    //which u want to send into your eg. listbox

    data[0] = data; //my stored data in array

    //for better understanding, this method "Button_Click_1" is called from Window1.xaml.cs
    //and I want to pass information into my another window Graph1.xaml.cs

    //create "newWindow" object onto your another window and send "data" by constuctor
    var newWindow = new Graph1(data); //line *
    //you can call this if u want to show that window after changes applied
    newWindow.Show();
}

After that your Graph1.xaml.cs should look like this: 

public partial class Graph1 : Window
{//this method takes over your data u sent by line * into previous method explained
    public Graph1(int[]data) 
    {
        InitializeComponent();
        //now you can direcly use your "data" or can call another method and pass your data into it
        ownListBoxUpdateMethod(data);

    }
    private void ownListBoxUpdateMethod(int[] data)
    {
        //update your listbox here and its done ;-)
    }
于 2013-03-07T10:02:14.243 回答
1

这个元素的绑定方向应该暴露给 TwoWay (Mode=TwoWay)

像这样：

x:Name="list" ItemsSource="{Binding ....... , Path=........., Mode=TwoWay}}" ......

除了默认绑定（一种方式）之外，您还可以将绑定配置为两种方式，一种方式到来源，等等。这是通过指定 Mode 属性来完成的。

OneWay：导致对源属性的更改自动更新目标属性，但源未更改 TwoWay：源或目标中的更改自动导致对另一个更新 OneWayToSource：导致对目标属性的更改自动更新源属性目标未更改 OneTime：仅导致对源属性的第一次更改会自动更新目标属性，但源不会更改，后续更改不会影响目标属性

你可以看看这个：http: //msdn.microsoft.com/en-us/library/ms752347.aspx

于 2013-03-07T08:17:25.500 回答